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-: Hello, again.
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In this lecture,
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we are going to discuss
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the Bernoulli Distribution.
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Before we begin,
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we use Bern
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to define
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a Bernoulli Distribution,
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followed by the probability
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of our preferred outcome
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in parenthesis.
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Therefore,
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we read the following statement as
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variable X follows
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a Bernoulli distribution
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with a probability of
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success equal to P.
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Okay.
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We need to describe what types
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of events follow a Bernoulli distribution.
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Any event where we only have one trial
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and two possible outcomes
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follows such a distribution.
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These may include a coin flip,
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a single true or false quiz question,
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or deciding whether to vote
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for the Democratic or Republican parties
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in the U.S. elections.
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Usually,
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when dealing with a Bernoulli distribution,
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we either have the probabilities
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of one of the events occurring,
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or have past data indicating
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some experimental probability.
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In either case,
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the graph of a Bernoulli distribution is simple.
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It consists of two bars,
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one for each of the possible outcomes.
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One bar would rise up to its
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associated probability of P,
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and the other one would
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only reach one minus P.
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For Bernoulli distributions,
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we often have to assign which outcome is zero
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and which outcome is one.
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After doing so,
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we can calculate the expected value.
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Bear in mind that depending
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on how we assign the zero and the one,
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our expected value will be equal
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to either P or one minus P.
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We usually denote the higher probability
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with P and the lower one with one minus P.
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Furthermore, conventionally,
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we also assign a value
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of one to the event with
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the probability equal to P.
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That way the expected value
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expresses the likelihood
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of the favored event.
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Since we only have one trial
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and a favored event,
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we expect that outcome to occur.
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By plugging in
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P and one minus P
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into the variance formula,
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we find that the variance
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of Bernoulli events would always
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equal P times one minus P.
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That is true regardless of
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what the expected value is.
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Here's the first instance
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where we observe how
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elegant the characteristics
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of some distributions are.
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Once again,
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we can calculate the variance and
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standard deviation using the formulas
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we defined earlier,
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but they bring us little value.
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For example,
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consider flipping an unfair coin.
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This coin is called unfair
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because its weight is spread disproportionately,
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and it gets tails 60% of the time.
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We assign the outcome
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of tails to be one and P to equal 0.6.
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Therefore, the expected value would be P or 0.6.
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If we plug in this result
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into the variance formula,
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we would get a variance of
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0.6 times 0.4 or 0.24.
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Good job, everybody.
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Sometimes,
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instead of wanting to know which
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of two outcomes is more probable,
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we want to know how often it would
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occur over several trials.
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In such cases,
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the outcomes follow a binomial distribution,
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and we will explore it further in the next lecture.
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