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These are the user uploaded subtitles that are being translated: 0 00:00:00,000 --> 00:00:00,520 1 00:00:00,520 --> 00:00:04,030 Hi, my name's Josh Meisel, and I'm a graduate student in the biology 2 00:00:04,030 --> 00:00:05,780 department of MIT. 3 00:00:05,780 --> 00:00:09,140 And my deep dive is on modes of inheritance. 4 00:00:09,140 --> 00:00:15,960 I study the genetics of host pathogen interactions in worms. 5 00:00:15,960 --> 00:00:19,070 But today, we're going to use Drosophila-- 6 00:00:19,070 --> 00:00:19,810 fruit flies-- 7 00:00:19,810 --> 00:00:23,940 as a model system to understand mode of inheritance-- 8 00:00:23,940 --> 00:00:26,880 how traits are inherited. 9 00:00:26,880 --> 00:00:31,630 So what we have here on the left is two flies-- 10 00:00:31,630 --> 00:00:36,610 a wild type female fly that has wings and a mutant fly-- 11 00:00:36,610 --> 00:00:40,090 a male mutant fly that does not have wings. 12 00:00:40,090 --> 00:00:45,650 And we're interested in how this wingless trait is being inherited. 13 00:00:45,650 --> 00:00:48,700 Is it being inherited in a dominant or recessive fashion? 14 00:00:48,700 --> 00:00:51,045 In an autosomal or sex-linked fashion? 15 00:00:51,045 --> 00:00:52,340 And we're going to do crosses. 16 00:00:52,340 --> 00:00:55,710 We're going to do experiments and analyze the results to distinguish 17 00:00:55,710 --> 00:00:57,570 between these possibilities. 18 00:00:57,570 --> 00:01:03,080 So the first question that we're going to ask is, is the wingless trait, 19 00:01:03,080 --> 00:01:08,090 which is being caused by a mutation in some unknown gene, being inherited in 20 00:01:08,090 --> 00:01:12,750 a recessive or dominant fashion? 21 00:01:12,750 --> 00:01:16,180 And what we're going to do to answer this question is we're going to cross 22 00:01:16,180 --> 00:01:20,420 our wild type female flies to our male mutant flies. 23 00:01:20,420 --> 00:01:23,340 And we're going to call these the P0 generation 24 00:01:23,340 --> 00:01:24,590 because there are parentals. 25 00:01:24,590 --> 00:01:26,780 26 00:01:26,780 --> 00:01:29,200 We have our wild type female fly. 27 00:01:29,200 --> 00:01:33,960 We're going to cross it to our wingless male fly. 28 00:01:33,960 --> 00:01:38,010 And all the progeny in the F1 generation are wild type. 29 00:01:38,010 --> 00:01:38,870 They all have wings. 30 00:01:38,870 --> 00:01:43,550 So this tells us that the wingless trait is being inherited in a 31 00:01:43,550 --> 00:01:44,720 recessive manner. 32 00:01:44,720 --> 00:01:49,310 Now we can give symbols to the alleles of this unknown gene, which is causing 33 00:01:49,310 --> 00:01:51,160 the wingless phenotype. 34 00:01:51,160 --> 00:01:54,690 Because it's recessive, we're going to give the mutant allele-- we're going 35 00:01:54,690 --> 00:02:00,160 to denote that as lowercase "wg." And the wild type allele we're going to 36 00:02:00,160 --> 00:02:01,420 know with a "plus." 37 00:02:01,420 --> 00:02:05,160 Now the second question we want to ask is whether this trait is being 38 00:02:05,160 --> 00:02:07,070 inherited in a sex-linked manner. 39 00:02:07,070 --> 00:02:12,800 That is, does the gene responsible for the wingless trait reside on a sex 40 00:02:12,800 --> 00:02:13,510 chromosome? 41 00:02:13,510 --> 00:02:16,320 Or is it being inherited in an autosomal manner? 42 00:02:16,320 --> 00:02:21,420 That is, is the gene responsible for the wingless trait residing on one of 43 00:02:21,420 --> 00:02:23,820 the non-sex chromosomes? 44 00:02:23,820 --> 00:02:28,720 Let's write out the genotypes of our flies so far for each scenario, 45 00:02:28,720 --> 00:02:30,370 autosomal and sex-linked. 46 00:02:30,370 --> 00:02:34,300 First, we'll write out the genotypes assuming the 47 00:02:34,300 --> 00:02:35,980 wingless trait is autosomal. 48 00:02:35,980 --> 00:02:42,390 Our wild type fly has two wild type copies of this gene. 49 00:02:42,390 --> 00:02:47,625 Our wingless male fly that we started with has two mutant 50 00:02:47,625 --> 00:02:49,020 copies of this gene. 51 00:02:49,020 --> 00:02:54,020 And our F1 progeny will all be heterozygotes for the mutant allele. 52 00:02:54,020 --> 00:02:58,820 And since the wingless phenotype is recessive, all the F1 progeny are wild 53 00:02:58,820 --> 00:03:00,620 type and have wings. 54 00:03:00,620 --> 00:03:05,610 Now let's write the phenotype in the scenario where the wingless trait is 55 00:03:05,610 --> 00:03:07,230 sex-linked. 56 00:03:07,230 --> 00:03:12,770 Our wild type fly has two wild type copies of the X chromosome. 57 00:03:12,770 --> 00:03:17,440 When we're dealing with sex-linked genes, we write the allelic symbol as 58 00:03:17,440 --> 00:03:19,460 a superscript over the X chromosome. 59 00:03:19,460 --> 00:03:23,510 We also assume that sex-linked genes reside on the X chromome, not the Y 60 00:03:23,510 --> 00:03:25,980 chromosome, because there are very few genes on the Y chromosome. 61 00:03:25,980 --> 00:03:29,340 The vast majority of sex-linked genes reside on the X chromosome. 62 00:03:29,340 --> 00:03:35,950 Our wingless male has a copy of the X chromosome with the wingless allele, 63 00:03:35,950 --> 00:03:38,150 and a Y chromosome because it's a male. 64 00:03:38,150 --> 00:03:44,500 The F1 progeny then can either get a wild type X chromosome from their 65 00:03:44,500 --> 00:03:49,450 mother, and a mutant X chromosome from their father. 66 00:03:49,450 --> 00:03:51,520 These files are female. 67 00:03:51,520 --> 00:03:54,950 Or if they can get a wild type copy of the X chromosome from their mother and 68 00:03:54,950 --> 00:03:56,710 a Y chromosome from their father. 69 00:03:56,710 --> 00:03:57,950 These flies are male. 70 00:03:57,950 --> 00:04:00,650 And both these flies will have the wild type phenotype. 71 00:04:00,650 --> 00:04:02,370 They'll both have wings. 72 00:04:02,370 --> 00:04:05,770 Again, the male has one wild type copy of the X chromosome. 73 00:04:05,770 --> 00:04:09,130 And the female is a heterozygote, and since the wingless phenotype is 74 00:04:09,130 --> 00:04:11,050 recessive, those flies will have wings. 75 00:04:11,050 --> 00:04:14,680 So from this first cross, we cannot determine whether this trait is 76 00:04:14,680 --> 00:04:18,290 sex-linked, as in this scenario, or autosomal in this scenario. 77 00:04:18,290 --> 00:04:20,110 The data is consistent with both of these. 78 00:04:20,110 --> 00:04:21,750 So we need to do another cross. 79 00:04:21,750 --> 00:04:25,860 And this cross will involve mating F1 siblings with each other. 80 00:04:25,860 --> 00:04:31,230 So in an autosomal scenario, we'll mate female, which is heterozygote-- 81 00:04:31,230 --> 00:04:33,530 plus over wingless-- 82 00:04:33,530 --> 00:04:36,150 to a male, which is also heterozygote-- 83 00:04:36,150 --> 00:04:38,260 plus over wingless. 84 00:04:38,260 --> 00:04:41,390 And now we're going to look at what the F2 progeny will 85 00:04:41,390 --> 00:04:42,640 be from this cross. 86 00:04:42,640 --> 00:04:46,190 87 00:04:46,190 --> 00:04:50,030 We can use a Punnett square as a tool. 88 00:04:50,030 --> 00:04:54,570 So from their mother, the gametes produced will be plus and wingless in 89 00:04:54,570 --> 00:04:55,650 equal numbers. 90 00:04:55,650 --> 00:04:59,080 And from their father, plus and wingless in equal numbers, resulting 91 00:04:59,080 --> 00:05:03,300 in a quarter of twos that are plus over plus, which will be wild type. 92 00:05:03,300 --> 00:05:06,990 Quarter which will be plus over wingless, which is wild type. 93 00:05:06,990 --> 00:05:09,640 Another quarter, which will be plus over wingless. 94 00:05:09,640 --> 00:05:13,570 And finally a quarter, which will be wingless over wingless, resulting in 95 00:05:13,570 --> 00:05:18,060 3/4 wild type and one quarter wingless. 96 00:05:18,060 --> 00:05:20,280 What will happen in the sex-linked scenario? 97 00:05:20,280 --> 00:05:23,600 We're going to mate these F1 siblings with each other. 98 00:05:23,600 --> 00:05:25,150 Let's draw a Punnett square again. 99 00:05:25,150 --> 00:05:29,170 And the gametes produced by the F1s-- let's see. 100 00:05:29,170 --> 00:05:34,830 The mother will produce a wild type X chromosome, and a mutant X chromosome. 101 00:05:34,830 --> 00:05:39,360 And the father will produce a wild type X chromosome, and a Y chromosome. 102 00:05:39,360 --> 00:05:46,250 So the F2 progeny will either be wild type X over wild type X. These will be 103 00:05:46,250 --> 00:05:49,440 wild type females. 104 00:05:49,440 --> 00:05:53,890 They could be wild type X over mutant X. These will be 105 00:05:53,890 --> 00:05:56,140 also wild type females. 106 00:05:56,140 --> 00:06:00,990 They could be wild type X over Y. These will be wild type males. 107 00:06:00,990 --> 00:06:09,080 Or they could be mutant X over Y. These will be wingless males. 108 00:06:09,080 --> 00:06:16,720 So what that breaks down to is all the females be wild type, and one half of 109 00:06:16,720 --> 00:06:21,610 the males will be wild type, and one half of the males will be wingless. 110 00:06:21,610 --> 00:06:25,750 Notice that, just like the autosomal scenario, a quarter of the F2s are 111 00:06:25,750 --> 00:06:26,900 mutant wingless. 112 00:06:26,900 --> 00:06:31,470 But in this case, all of the flies with the wingless phenotype are male. 113 00:06:31,470 --> 00:06:37,670 Whereas in the autosomal scenario, the wingless F2s are an equal mixture of 114 00:06:37,670 --> 00:06:39,040 males and females. 115 00:06:39,040 --> 00:06:43,950 And in this way, we can determine, by comparing the data from this cross, 116 00:06:43,950 --> 00:06:48,470 the wingless trait is being inherited in an autosomal or sex-linked manner. 117 00:06:48,470 --> 00:06:52,110 So we've determined successfully that the wingless trait is being inherited 118 00:06:52,110 --> 00:06:53,280 in a recessive fashion. 119 00:06:53,280 --> 00:06:57,120 Now, we're going to turn to a slightly more complicated example and analyze 120 00:06:57,120 --> 00:07:00,520 the mode of inheritance of a fly with a wrinkled wing. 121 00:07:00,520 --> 00:07:04,540 Now we're going to do a slightly more difficult scenario. 122 00:07:04,540 --> 00:07:09,490 So imagine again that we're given a wild type female fly. 123 00:07:09,490 --> 00:07:13,560 And now we're going to be given a new mutant. 124 00:07:13,560 --> 00:07:17,620 This mutant is a male that has curly wings. 125 00:07:17,620 --> 00:07:24,060 So once again, the first thing we're going to do is determine whether this 126 00:07:24,060 --> 00:07:29,030 trait, this wrinkled wing trait, is being inherited in a dominant or 127 00:07:29,030 --> 00:07:30,160 recessive manner. 128 00:07:30,160 --> 00:07:35,580 So we're going to mate our wild type female flies to our 129 00:07:35,580 --> 00:07:37,270 wrinkled male flies. 130 00:07:37,270 --> 00:07:42,710 And in the F1 generation, this time what we get is one half wild type 131 00:07:42,710 --> 00:07:47,270 flies and one half wrinkled flies. 132 00:07:47,270 --> 00:07:50,550 This tells us that the wrinkled trait is being inherited 133 00:07:50,550 --> 00:07:52,490 in a dominant fashion. 134 00:07:52,490 --> 00:07:57,200 So now we can give symbols to the alleles in this problem. 135 00:07:57,200 --> 00:08:06,180 We'll denote the wrinkled allele as capital "WR," 136 00:08:06,180 --> 00:08:07,600 because this is dominant. 137 00:08:07,600 --> 00:08:11,750 And we'll denote the wild type allele as "plus." Now we'll try and determine 138 00:08:11,750 --> 00:08:15,330 if this wrinkled trait is being inherited in a sex-linked 139 00:08:15,330 --> 00:08:16,930 or autosomal manner. 140 00:08:16,930 --> 00:08:20,950 Now we're going to do a slightly more difficult scenario. 141 00:08:20,950 --> 00:08:25,890 So imagine again that we're given a wild type female fly. 142 00:08:25,890 --> 00:08:30,010 And now we're going to be given a new mutant. 143 00:08:30,010 --> 00:08:34,039 This mutant is a male that has curly wings. 144 00:08:34,039 --> 00:08:40,470 So once again, the first thing we're going to do is determine whether this 145 00:08:40,470 --> 00:08:45,420 trait, this wrinkled wing trait, is being inherited in a dominant or 146 00:08:45,420 --> 00:08:46,550 recessive manner. 147 00:08:46,550 --> 00:08:52,000 So we're going to mate our wild type female flies to our 148 00:08:52,000 --> 00:08:53,730 wrinkled male flies. 149 00:08:53,730 --> 00:08:58,540 And in the F1 generation, this time what we get is wild type females would 150 00:08:58,540 --> 00:09:01,320 be X plus over X plus. 151 00:09:01,320 --> 00:09:08,710 The wrinkled males would be X wrinkled over Y. And the F1s then would be one 152 00:09:08,710 --> 00:09:12,370 half X plus over X wrinkled. 153 00:09:12,370 --> 00:09:15,130 These would be wrinkled females. 154 00:09:15,130 --> 00:09:20,200 And one half X plus over Y. These would be wild type males. 155 00:09:20,200 --> 00:09:24,310 So the data we have is consistent with this hypothesis that the wrinkled 156 00:09:24,310 --> 00:09:26,930 trait is being inherited in a dominant sex-linked fashion. 157 00:09:26,930 --> 00:09:31,580 But it requires that all of the wrinkled flies in the F1 158 00:09:31,580 --> 00:09:33,580 generation be female. 159 00:09:33,580 --> 00:09:37,560 Let's imagine that this is not the case-- that the wrinkled flies in the 160 00:09:37,560 --> 00:09:41,130 wild type flies in the F1 generation are in equal distribution 161 00:09:41,130 --> 00:09:42,260 of males and females. 162 00:09:42,260 --> 00:09:47,090 Is there any way that this data could be consistent with either the 163 00:09:47,090 --> 00:09:49,120 sex-linked or the autosomal hypothesis? 164 00:09:49,120 --> 00:09:52,680 Well, let's go back to the autosomal scenario. 165 00:09:52,680 --> 00:09:57,140 And we assumed that the wrinkled male here was homozygous for 166 00:09:57,140 --> 00:09:58,190 the wrinkled allele. 167 00:09:58,190 --> 00:10:00,200 But what if it was a heterozygote? 168 00:10:00,200 --> 00:10:04,790 The wrinkled male that we're given would still appear wrinkled because 169 00:10:04,790 --> 00:10:06,510 the wrinkled phenotype is dominant. 170 00:10:06,510 --> 00:10:14,050 But now when we did the cross, half of the F1s would be plus over plus. 171 00:10:14,050 --> 00:10:19,090 And half of the F1s would be plus over wrinkled, giving us half wild type 172 00:10:19,090 --> 00:10:23,820 flies of both genders and half wrinkled files of both genders 173 00:10:23,820 --> 00:10:26,210 consistent with the data that we were given. 174 00:10:26,210 --> 00:10:30,960 So from this, we can conclude that the wrinkled phenotype is being inherited 175 00:10:30,960 --> 00:10:32,910 in a dominant autosomal fashion. 176 00:10:32,910 --> 00:10:36,110 And that the original wrinkled mutant fly that we were given was a 177 00:10:36,110 --> 00:10:37,000 heterozygote. 178 00:10:37,000 --> 00:10:41,120 So I've taken you through two sets of experiments that you can use to 179 00:10:41,120 --> 00:10:44,700 determine whether a mutant phenotype is being inherited in a recessive or 180 00:10:44,700 --> 00:10:47,170 dominant fashion, or a sex-linked or autosomal fashion. 181 00:10:47,170 --> 00:10:49,840 And these are the kind of experiments that we do in the lab when we're 182 00:10:49,840 --> 00:10:51,090 presented with mutants. 183 00:10:51,090 --> 00:10:54,120 184 00:10:54,120 --> 00:10:57,080 So today you've learned how to experimentally tell the difference 185 00:10:57,080 --> 00:11:00,975 between a trait that's being inherited in an autosomal fashion versus a 186 00:11:00,975 --> 00:11:02,070 sex-linked fashion. 187 00:11:02,070 --> 00:11:04,700 We also learned how to tell the difference experimentally between a 188 00:11:04,700 --> 00:11:07,710 trait that is recessive versus dominant. 189 00:11:07,710 --> 00:11:08,960 So thanks for listening. 190 00:11:08,960 --> 00:11:09,660 16049

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