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These are the user uploaded subtitles that are being translated: 1 00:00:00.02 --> 00:00:02.05 - [Instructor] We now have the window locations 2 00:00:02.05 --> 00:00:04.04 and base geometry generated 3 00:00:04.04 --> 00:00:07.06 within our dynamo script from the inputs provided. 4 00:00:07.06 --> 00:00:09.09 Now let's take a look at the evaluator section 5 00:00:09.09 --> 00:00:11.00 of the script. 6 00:00:11.00 --> 00:00:13.02 Which is where we will provide the methods 7 00:00:13.02 --> 00:00:16.02 for the study to determine whether one generated option 8 00:00:16.02 --> 00:00:18.09 is better or worse than another. 9 00:00:18.09 --> 00:00:21.09 I currently have the exercise files open for this lesson. 10 00:00:21.09 --> 00:00:24.07 Which is where we left off from in the last lesson. 11 00:00:24.07 --> 00:00:27.06 So let's start by grouping the Curve.Points 12 00:00:27.06 --> 00:00:29.03 at eco segment length node, 13 00:00:29.03 --> 00:00:37.05 to indicate that it is a type of generator. 14 00:00:37.05 --> 00:00:40.03 Next let's look at the evaluator section 15 00:00:40.03 --> 00:00:43.03 underneath this evaluators title. 16 00:00:43.03 --> 00:00:46.00 There are two main metrics that we'll need to evaluate 17 00:00:46.00 --> 00:00:47.09 for each option generated. 18 00:00:47.09 --> 00:00:51.05 The first is how much length the windows have occupied 19 00:00:51.05 --> 00:00:53.00 along the wall. 20 00:00:53.00 --> 00:00:54.05 The intent of the study, 21 00:00:54.05 --> 00:00:58.02 is to maximize the amount of window length along the wall. 22 00:00:58.02 --> 00:01:01.00 So we need to compare the total wall length 23 00:01:01.00 --> 00:01:03.03 with the total window length. 24 00:01:03.03 --> 00:01:06.00 The smaller the difference, the closer the windows are 25 00:01:06.00 --> 00:01:08.05 to occupying the entire length of the wall. 26 00:01:08.05 --> 00:01:10.06 Of course if there are too many windows, 27 00:01:10.06 --> 00:01:11.07 there would be an overlap 28 00:01:11.07 --> 00:01:14.02 and the scale would be falsely low. 29 00:01:14.02 --> 00:01:16.09 Which is why we need the second evaluator. 30 00:01:16.09 --> 00:01:21.02 The second evaluator, is needed to calculate the overlap 31 00:01:21.02 --> 00:01:24.08 of the windows using the cuboids that we created 32 00:01:24.08 --> 00:01:29.03 in the last lesson. 33 00:01:29.03 --> 00:01:30.01 For example 34 00:01:30.01 --> 00:01:34.03 if we increase the number of wall segment lengths, 35 00:01:34.03 --> 00:01:37.00 eventually it will become one large mass 36 00:01:37.00 --> 00:01:39.03 which is not really what we want. 37 00:01:39.03 --> 00:01:41.02 Ideally, there is no overlap 38 00:01:41.02 --> 00:01:45.00 and a space between each window. 39 00:01:45.00 --> 00:01:47.01 So let's start with the first evaluator 40 00:01:47.01 --> 00:01:49.05 to determine the remaining length of the wall, 41 00:01:49.05 --> 00:01:52.07 once the windows are placed. 42 00:01:52.07 --> 00:01:55.04 For this we'll first need the length of the wall. 43 00:01:55.04 --> 00:01:59.01 And we can obtain that from using the Curve.Length node. 44 00:01:59.01 --> 00:02:01.07 To find this we can right click the canvas 45 00:02:01.07 --> 00:02:06.02 and search Curve.Length. 46 00:02:06.02 --> 00:02:09.02 For the input, let's use the location line of the wall, 47 00:02:09.02 --> 00:02:11.02 which we retrieved earlier 48 00:02:11.02 --> 00:02:15.05 coming from this Data.Remember node. 49 00:02:15.05 --> 00:02:17.06 From this length we need to subtract 50 00:02:17.06 --> 00:02:19.05 the total length of the windows. 51 00:02:19.05 --> 00:02:23.01 So for that let's first get the number of windows placed 52 00:02:23.01 --> 00:02:28.02 using a Count node. 53 00:02:28.02 --> 00:02:29.04 And we'll plug into that, 54 00:02:29.04 --> 00:02:32.08 the points that we generated earlier. 55 00:02:32.08 --> 00:02:35.07 So we can say there are 10 windows placed. 56 00:02:35.07 --> 00:02:37.06 To get the total length. 57 00:02:37.06 --> 00:02:41.04 We then need a Multiplication node. 58 00:02:41.04 --> 00:02:44.01 So we'll search Multiplication 59 00:02:44.01 --> 00:02:46.08 and we're going to multiply the number of windows 60 00:02:46.08 --> 00:02:49.00 by the selected window width 61 00:02:49.00 --> 00:02:56.01 which is coming from this List.GetItemAt index node. 62 00:02:56.01 --> 00:02:56.09 Perfect. 63 00:02:56.09 --> 00:03:00.06 So we have a total length of 4,060 millimeters 64 00:03:00.06 --> 00:03:05.07 for the windows and 8,750 for the wall length. 65 00:03:05.07 --> 00:03:08.02 Now we can subtract this wall length 66 00:03:08.02 --> 00:03:09.04 by the window length. 67 00:03:09.04 --> 00:03:16.06 To do that let's use a subtraction node. 68 00:03:16.06 --> 00:03:17.04 Great. 69 00:03:17.04 --> 00:03:20.00 So we have a value which we can optimize. 70 00:03:20.00 --> 00:03:22.09 Ideally, we want this to be as low as possible 71 00:03:22.09 --> 00:03:25.01 without the windows overlapping. 72 00:03:25.01 --> 00:03:26.09 So let's finish the logic for that. 73 00:03:26.09 --> 00:03:27.07 As we can see 74 00:03:27.07 --> 00:03:31.02 I've already set up most of the nodes for this section. 75 00:03:31.02 --> 00:03:33.02 The first two nodes are used to calculate 76 00:03:33.02 --> 00:03:36.09 the overall volume, of all of the windows. 77 00:03:36.09 --> 00:03:42.03 So if we plug the cuboids into the Solid.Volume node 78 00:03:42.03 --> 00:03:43.07 we get a value, 79 00:03:43.07 --> 00:03:47.05 which is the sum of each windows volume. 80 00:03:47.05 --> 00:03:51.08 The two nodes below, I used to first union the solids 81 00:03:51.08 --> 00:03:53.09 and then calculate the volume. 82 00:03:53.09 --> 00:03:58.01 So if we plug those cuboids into the Solid.By union node, 83 00:03:58.01 --> 00:04:01.04 we also get a value from the Solid.Volume node. 84 00:04:01.04 --> 00:04:03.08 Which is equal to the sum node. 85 00:04:03.08 --> 00:04:08.06 And this is because the windows are not overlapping. 86 00:04:08.06 --> 00:04:10.04 If it was to increase the number of windows, 87 00:04:10.04 --> 00:04:14.02 that they start to overlap, 88 00:04:14.02 --> 00:04:16.05 we can say that this number differs. 89 00:04:16.05 --> 00:04:19.02 This is because the Math.Sum node 90 00:04:19.02 --> 00:04:21.09 is summing all of the windows volumes. 91 00:04:21.09 --> 00:04:24.07 However the second Solid.Volume node, 92 00:04:24.07 --> 00:04:29.07 is first combining all of the windows to create one mass. 93 00:04:29.07 --> 00:04:33.03 Next we have an equal two node and a subtraction node. 94 00:04:33.03 --> 00:04:36.01 The equal node checks if these two nodes 95 00:04:36.01 --> 00:04:38.08 are outputting equal values. 96 00:04:38.08 --> 00:04:39.08 Currently they're not. 97 00:04:39.08 --> 00:04:41.07 So it's false. 98 00:04:41.07 --> 00:04:44.04 The subtraction node is used to determine 99 00:04:44.04 --> 00:04:47.06 the difference of these two nodes. 100 00:04:47.06 --> 00:04:52.00 These two values are then used with this if statement node. 101 00:04:52.00 --> 00:04:53.08 The if statement node will check 102 00:04:53.08 --> 00:04:56.03 if the two values are equal. 103 00:04:56.03 --> 00:04:59.05 If they are equal, meaning there's no overlap, 104 00:04:59.05 --> 00:05:02.03 then it'll output a value of zero. 105 00:05:02.03 --> 00:05:07.07 If they are not equal, it'll output this difference value. 106 00:05:07.07 --> 00:05:09.07 Because they are currently not equal, 107 00:05:09.07 --> 00:05:11.08 it is outputting that difference value. 108 00:05:11.08 --> 00:05:14.03 Ideally, we want this to be zero, 109 00:05:14.03 --> 00:05:16.05 meaning there's no overlap. 110 00:05:16.05 --> 00:05:18.00 Both of our evaluators, 111 00:05:18.00 --> 00:05:20.02 output a value which we can use to score 112 00:05:20.02 --> 00:05:22.04 each generated option. 113 00:05:22.04 --> 00:05:26.00 Ideally, we want the window to wall length to be low 114 00:05:26.00 --> 00:05:29.06 and we want the window overlap to be outputting zero. 115 00:05:29.06 --> 00:05:32.03 So next let's set up the outputs 116 00:05:32.03 --> 00:05:34.00 so that the study can assess them. 9135