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These are the user uploaded subtitles that are being translated: 1 00:00:00,440 --> 00:00:02,300 Now let's talk a little bit about control. 2 00:00:03,560 --> 00:00:06,080 Again, I'm gonna focus on the vertical direction. 3 00:00:07,590 --> 00:00:10,550 So let's think about controlling height. 4 00:00:10,550 --> 00:00:14,326 What you would like to do is to drive the robot to a desired vertical position 5 00:00:14,326 --> 00:00:17,361 either up or down. 6 00:00:19,510 --> 00:00:22,620 Let's use x to measure the vertical displacement. 7 00:00:25,330 --> 00:00:28,940 Clearly, the acceleration is given by the second derivative of position. 8 00:00:30,600 --> 00:00:34,899 If you look on the left hand side, you'll see the sum of the forces. 9 00:00:35,960 --> 00:00:40,420 Let's call u the sum of the forces divided by the mass. 10 00:00:41,740 --> 00:00:48,778 So you have now a very simple second order differential equation with an input u and 11 00:00:48,778 --> 00:00:54,293 a variable x, such that u is equal to the second derivative of x. 12 00:00:54,293 --> 00:01:00,476 Our goal to control this vehicle is to determine the function u, 13 00:01:00,476 --> 00:01:05,640 such that the vehicle goes to the desired position x. 14 00:01:08,160 --> 00:01:09,610 So here is the control problem. 15 00:01:10,760 --> 00:01:13,980 The system we have is a very simple system. 16 00:01:13,980 --> 00:01:15,920 It's a second order linear system. 17 00:01:17,200 --> 00:01:22,980 You're trying to figure out what u of t, what function of t that is u, 18 00:01:22,980 --> 00:01:27,260 drives x to a desired position x desired. 19 00:01:27,260 --> 00:01:29,840 If you have a desired trajectory, 20 00:01:29,840 --> 00:01:35,270 in other words x desired is a function of time, you want to synthesize the control 21 00:01:35,270 --> 00:01:39,900 input u of t that allows the vehicle to follow the desired trajectory. 22 00:01:42,000 --> 00:01:44,030 In order to do that let's define an error. 23 00:01:45,140 --> 00:01:48,470 The error function is essentially the difference between the desired trajectory 24 00:01:48,470 --> 00:01:49,580 and the actual trajectory. 25 00:01:51,840 --> 00:01:54,330 So the larger the error, obviously, 26 00:01:54,330 --> 00:01:58,870 the further the deviation from the actual trajectory, from the desire trajectory. 27 00:02:00,320 --> 00:02:03,920 What you'd like to do is to take this error and decrease it to zero. 28 00:02:05,180 --> 00:02:08,340 More specifically we want this error to go exponentially to zero. 29 00:02:10,250 --> 00:02:13,600 In other words, we wanna find u of t, 30 00:02:13,600 --> 00:02:17,970 such that the error function satisfies the second order differential equation. 31 00:02:19,360 --> 00:02:21,620 Why this differential equation? 32 00:02:21,620 --> 00:02:25,510 Well, in this differential equation, there are two unknowns, Kp and Kv. 33 00:02:26,550 --> 00:02:29,520 If I select appropriate values of Kp and 34 00:02:29,520 --> 00:02:34,920 Kv, more specifically, if I ensure that these values are positive, 35 00:02:34,920 --> 00:02:37,900 I can guarantee that this error will go exponentially to zero. 36 00:02:40,640 --> 00:02:44,530 The control input that achieves that is given by this very simple equation. 37 00:02:45,780 --> 00:02:49,200 Again, the only reason I'm pulling out this control equation 38 00:02:49,200 --> 00:02:52,270 is because I want the error to go exponentially to zero. 39 00:02:52,270 --> 00:02:55,050 And that'll ensure that x tends to x desired. 40 00:02:57,500 --> 00:03:04,540 There are two variables in this equation, one is K sub p, and the other is K sub v. 41 00:03:04,540 --> 00:03:09,370 You'll see that K sub p multiplies the error, and 42 00:03:09,370 --> 00:03:13,360 adds the error times Kp to the control function. 43 00:03:15,000 --> 00:03:18,400 K sub v multiplies the derivative of the error, and 44 00:03:18,400 --> 00:03:21,140 adds that to the control function. 45 00:03:21,140 --> 00:03:25,820 So one is called the proportional gain, the other is called the derivative gain. 46 00:03:25,820 --> 00:03:30,480 And in addition, you need some knowledge of how you want the trajectory to vary. 47 00:03:30,480 --> 00:03:35,920 So you're feeding forward the second derivative of the desired trajectory. 48 00:03:35,920 --> 00:03:38,690 This is often called the feedforward term. 49 00:03:38,690 --> 00:03:41,390 And this completes your control law or 50 00:03:41,390 --> 00:03:45,520 the control equation at then you can use to drive your motors. 51 00:03:47,540 --> 00:03:51,300 Here's a typical response of what the error might look like if you use such 52 00:03:51,300 --> 00:03:52,400 an approach to control. 53 00:03:53,960 --> 00:03:58,780 The error starts out being non zero, but quickly settles down to the zero value. 54 00:03:59,960 --> 00:04:04,180 The error might undershoot, go from a positive value to a negative value, but 55 00:04:04,180 --> 00:04:06,210 eventually you're guaranteed that it'll go to zero. 56 00:04:07,460 --> 00:04:13,240 To summarize, we've derived a very simple control law. 57 00:04:13,240 --> 00:04:16,820 It's called the proportional plus derivative control law, 58 00:04:16,820 --> 00:04:18,870 which has a very simple form. 59 00:04:18,870 --> 00:04:23,761 It has three terms, a feedforward term, a proportional term, and a derivative term. 60 00:04:23,761 --> 00:04:26,620 Each of these terms has a significance. 61 00:04:27,710 --> 00:04:33,180 The proportional term acts like a spring or a capacitance. 62 00:04:33,180 --> 00:04:35,909 The higher the proportional term is, 63 00:04:35,909 --> 00:04:41,035 the more springy the system becomes and more likely it is to overshoot. 64 00:04:41,035 --> 00:04:48,910 The higher the derivative term, the more dense it becomes. 65 00:04:48,910 --> 00:04:53,150 So this is like a viscous dashpot or a resistance in an electrical system. 66 00:04:56,110 --> 00:05:01,260 By increasing the derivative gain, the system essentially gets damped, 67 00:05:01,260 --> 00:05:05,300 and you can make it overdamped so that it never overshoots the desired value. 68 00:05:06,760 --> 00:05:10,150 In exceptional cases, you might consider using 69 00:05:10,150 --> 00:05:13,710 a more sophisticated version of the proportional plus derivative control. 70 00:05:14,710 --> 00:05:20,440 Here you have an extra term, which is proportional to the integral of the error. 71 00:05:21,600 --> 00:05:25,370 You often do this when you don't know the model exactly. 72 00:05:25,370 --> 00:05:28,990 So, for instance, you might not know the mass, or 73 00:05:28,990 --> 00:05:32,290 there might be some wind resistance that you need to overcome, and 74 00:05:32,290 --> 00:05:35,730 you don't know a priori how much this wind resistance is. 75 00:05:35,730 --> 00:05:40,010 The last term essentially allows you to compensate for 76 00:05:40,010 --> 00:05:45,230 unknown effects caused by either unknown quantities, or 77 00:05:45,230 --> 00:05:49,245 unknown wind conditions, or disturbances. 78 00:05:50,465 --> 00:05:54,535 The downside of adding this additional term is that your differential equation 79 00:05:54,535 --> 00:05:57,435 now becomes a third-order differential equation. 80 00:05:57,435 --> 00:06:01,555 The reason for that is you've suddenly added an integral in the mix and 81 00:06:01,555 --> 00:06:05,205 if you want to eliminate the integral you have to differentiate the whole equation 82 00:06:05,205 --> 00:06:08,256 one more time introducing a third derivative. 83 00:06:10,170 --> 00:06:13,370 However, the benefit of this is that this integral term will 84 00:06:13,370 --> 00:06:15,710 make the error go to zero eventually. 85 00:06:18,220 --> 00:06:23,040 So here are three examples of the system based 86 00:06:23,040 --> 00:06:27,440 on what values you pick for the proportional gain and the derivative gain. 87 00:06:29,630 --> 00:06:31,350 If both the gains are positive, 88 00:06:31,350 --> 00:06:34,280 you're guaranteed stability, as you see on the left side. 89 00:06:36,150 --> 00:06:41,680 If K sub v is equal to 0, then you're guaranteed marginal stability. 90 00:06:41,680 --> 00:06:44,080 While the system will not drift, 91 00:06:44,080 --> 00:06:46,669 you'll find it'll oscillate about the desired value. 92 00:06:48,590 --> 00:06:49,610 Of course, if one or 93 00:06:49,610 --> 00:06:53,770 the other gain is negative, then you essentially get an unstable system. 94 00:06:55,850 --> 00:07:00,026 You can similarly explore the effect of the integral gain which we haven't done in 95 00:07:00,026 --> 00:07:00,822 this picture. 96 00:07:00,822 --> 00:07:04,944 I now want to deal with a complete simulation of the quadrotor. 97 00:07:06,860 --> 00:07:11,230 Because we'll now require three independent direction 98 00:07:11,230 --> 00:07:14,940 we're gonna now introduce x, y, and z coordinates. 99 00:07:14,940 --> 00:07:16,860 And this time the z coordinate points up. 100 00:07:19,240 --> 00:07:22,366 So here's a simulation of the quadrotor and again, 101 00:07:22,366 --> 00:07:26,495 we're using a proportional derivative control to control height. 102 00:07:26,495 --> 00:07:31,260 For the moment, we're ignoring the other variables. 103 00:07:31,260 --> 00:07:35,930 We're adding terms to make sure that the lateral displacement is zero, the roll and 104 00:07:35,930 --> 00:07:38,850 pitch stays zero, and the yaw stays zero. 105 00:07:40,350 --> 00:07:43,230 But we don't have to worry about that for the present moment. 106 00:07:44,310 --> 00:07:47,460 We're only construing the proportional derivative control of height. 107 00:07:49,820 --> 00:07:54,285 And you can see that the error starts out being non-zero and 108 00:07:54,285 --> 00:07:56,702 then eventually settles down. 109 00:07:56,702 --> 00:08:01,627 There is an overshoot, the red curve overshoots the desired blue curve, but 110 00:08:01,627 --> 00:08:06,353 eventually settles back down so that the red and the blue curve coincide. 111 00:08:08,931 --> 00:08:12,550 And here's an experiment that demonstrates the same idea. 112 00:08:13,570 --> 00:08:15,870 The robot is asked to hover and 113 00:08:15,870 --> 00:08:20,590 in this case someone displaces the robot from the nominal hover position. 114 00:08:22,260 --> 00:08:24,830 And the robot fights to overcome the disturbance. 115 00:08:25,900 --> 00:08:30,620 Using a combination of proportional and derivative gains, the robot is able to 116 00:08:30,620 --> 00:08:35,370 compensate for that disturbance and then settle back down into the hover position. 117 00:08:37,340 --> 00:08:43,920 If you increase the value of Kp as I said earlier, the system gets more springy. 118 00:08:43,920 --> 00:08:48,170 So you can see that the system now overshoots. 119 00:08:48,170 --> 00:08:53,400 The red curve overshoots the blue step and then settles down eventually. 120 00:08:54,770 --> 00:08:58,910 Again, in this video you'll see the same phenomenon. 121 00:08:58,910 --> 00:09:03,480 The robot is hovering, but when it's displaced, when it recovers from 122 00:09:03,480 --> 00:09:08,850 the displaced position it overshoots and comes back to the original position. 123 00:09:08,850 --> 00:09:12,189 And this happens because the proportional gain has been increased. 124 00:09:15,511 --> 00:09:20,144 If you turn down this proportional gain, you lose the overshoot but 125 00:09:20,144 --> 00:09:22,750 instead you get a very soft response. 126 00:09:25,050 --> 00:09:25,690 And then, of course, 127 00:09:25,690 --> 00:09:29,110 if you turn up the derivative gain, the system becomes overdamped. 128 00:09:30,910 --> 00:09:33,380 So the overshoot disappears but 129 00:09:33,380 --> 00:09:37,780 the system takes also a longer time in order to get to the desired position. 130 00:09:40,160 --> 00:09:43,310 And once again, this video illustrates this. 131 00:09:43,310 --> 00:09:44,510 The vehicle is displaced. 132 00:09:45,550 --> 00:09:48,489 And it takes a longer time to get back to the original position. 133 00:09:53,026 --> 00:09:56,980 In order to get a feel for these different terms in the controller. 134 00:09:58,050 --> 00:09:59,620 Here's a simple exercise. 135 00:10:00,680 --> 00:10:04,300 You have a simulator of the system that you just saw. 136 00:10:06,320 --> 00:10:11,150 Try to play around with the two gains, K sub p and K sub v. 137 00:10:11,150 --> 00:10:18,900 To achieve a simple goal, which is to get a desired response in which the rise time, 138 00:10:18,900 --> 00:10:24,770 in other words the time taken to get to the desired position, is reasonably short. 139 00:10:24,770 --> 00:10:28,400 And the overshoot is kept below some modest value.12794

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