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These are the user uploaded subtitles that are being translated: 1 00:00:04,150 --> 00:00:07,679 This is a free, complete course for the CCNA. 2 00:00:07,679 --> 00:00:11,609 If you like these videos, please subscribe\n 3 00:00:11,609 --> 00:00:16,320 Also, please like and leave a comment, and\n 4 00:00:19,789 --> 00:00:23,189 In this video we will cover IPv6. 5 00:00:23,189 --> 00:00:28,868 As you already know, up to this point in the\n 6 00:00:28,868 --> 00:00:34,439 But IPv6 is the future, and it is starting\n 7 00:00:34,439 --> 00:00:40,209 IPv6 brings multiple improvements over IPv4,\n 8 00:00:41,640 --> 00:00:48,469 IPv6 is covered in a few areas of the official\nexam topics list. 9 00:00:48,469 --> 00:00:55,308 Topic 1.8 says you must be able to configure\n 10 00:00:55,308 --> 00:01:00,899 1.9 says you must be able to compare various\nIPv6 address types. 11 00:01:00,899 --> 00:01:05,760 You should also be able to configure and verify\n 12 00:01:07,829 --> 00:01:13,009 I considered trying to fit all of this into\n 13 00:01:14,400 --> 00:01:19,550 A lot of CCNA candidates don’t feel confident\n 14 00:01:19,549 --> 00:01:24,469 I think that’s because we spend so much\n 15 00:01:24,469 --> 00:01:28,400 just briefly cover IPv6 and then never mention\nit again. 16 00:01:28,400 --> 00:01:34,609 Let’s take our time to cover IPv6, and make\n 17 00:01:36,430 --> 00:01:39,090 Here’s what we’ll cover in this video. 18 00:01:39,090 --> 00:01:41,909 First, let’s review hexadecimal. 19 00:01:41,909 --> 00:01:47,329 I told you about hexadecimal when we covered\n 20 00:01:47,329 --> 00:01:52,620 understand hexadecimal, because IPv6 addresses\n 21 00:01:52,620 --> 00:01:56,960 Then I’ll give an overview of why IPv6 is\n 22 00:01:57,959 --> 00:02:05,609 I’ll give you a basic overview of IPv6,\n 23 00:02:05,609 --> 00:02:10,590 Finally I’ll show you how to configure IPv6\n 24 00:02:10,590 --> 00:02:15,430 Watch until the end of the video for a bonus\n 25 00:02:17,889 --> 00:02:23,458 I used them to study for my exams, and they\n 26 00:02:23,459 --> 00:02:29,128 If you want to get Boson ExSim, follow the\n 27 00:02:29,128 --> 00:02:34,389 Before talking about IPv6, you may be wondering,\n 28 00:02:34,389 --> 00:02:39,229 I think I mentioned this earlier in the course,\n 29 00:02:39,229 --> 00:02:44,128 Internet Stream Protocol was developed in\n 30 00:02:46,759 --> 00:02:53,469 It was never called IPv5, but it used a value\n 31 00:02:53,469 --> 00:02:58,098 If you remember, Day 10 of this course covered\n 32 00:03:00,030 --> 00:03:06,039 IPv4 uses a value of 4, and Internet Stream\n 33 00:03:06,039 --> 00:03:12,888 So, to avoid confusion, when the successor\n 34 00:03:12,889 --> 00:03:18,420 and it uses a value of 6 in the Version field\nof the header. 35 00:03:20,560 --> 00:03:25,500 The three numbering systems you should know\n 36 00:03:26,539 --> 00:03:32,519 0b can be used as a prefix before a binary\n 37 00:03:32,519 --> 00:03:34,090 For example, look at this number. 38 00:03:38,188 --> 00:03:41,919 Or binary 1 0, which is equal to decimal 2? 39 00:03:41,919 --> 00:03:46,818 Or is it perhaps hexadecimal 1 0, which is\n 40 00:03:48,400 --> 00:03:52,930 By using the prefix 0b, we can make it clear\n 41 00:03:52,930 --> 00:03:56,278 Now, why is ‘base 2’ another name for\nbinary? 42 00:03:56,278 --> 00:03:59,919 It’s because there are only two available\ndigits in binary. 43 00:04:01,810 --> 00:04:05,378 All numbers are represented using just these\ntwo digits. 44 00:04:05,378 --> 00:04:07,939 But you’re already familiar with binary. 45 00:04:07,939 --> 00:04:11,650 The next numbering system is decimal, or base\n10. 46 00:04:11,650 --> 00:04:15,239 You can use the prefix 0d to indicate decimal. 47 00:04:15,239 --> 00:04:18,199 As the name ‘base 10’ suggests, there\nare 10 available digits. 48 00:04:18,199 --> 00:04:22,709 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. 49 00:04:22,709 --> 00:04:27,649 Finally, there is hexadecimal, also known\nas base 16. 50 00:04:27,649 --> 00:04:32,560 You can use the prefix 0x to indicate hexadecimal,\n 51 00:04:34,610 --> 00:04:40,750 These are the 16 digits available in hexadecimal,\n 52 00:04:40,750 --> 00:04:44,449 B, C, D, E, and F are used as well. 53 00:04:44,449 --> 00:04:50,209 Here’s a chart comparing the three, from\n0 up to decimal 15. 54 00:04:50,209 --> 00:04:55,099 First, notice that up to 9, decimal and hexadecimal\n 55 00:04:55,100 --> 00:05:00,790 However, the decimal system then runs out\n 56 00:05:04,910 --> 00:05:11,920 Hexadecimal expresses the same value with\n 57 00:05:11,920 --> 00:05:18,970 D, 14 is E, and 15 is F. Okay, now let me\n 58 00:05:18,970 --> 00:05:22,510 Notice that these binary numbers have leading\n0s at the front. 59 00:05:22,509 --> 00:05:28,670 For example, decimal 3 is written as 0 0 1\n 60 00:05:28,670 --> 00:05:33,210 You don’t actually have to do this in binary,\n 61 00:05:33,209 --> 00:05:37,969 So, why did I write all of these numbers as\n 62 00:05:39,199 --> 00:05:46,639 It’s because I want to emphasize that each\n 63 00:05:46,639 --> 00:05:53,019 For example, the maximum value of four binary\n 64 00:05:54,569 --> 00:06:00,279 This is very important for converting between\n 65 00:06:00,279 --> 00:06:05,149 From this chart, I recommend memorizing the\n 66 00:06:05,149 --> 00:06:12,349 It’s not difficult, just remember that 10\n 67 00:06:12,350 --> 00:06:17,990 and 15 is F. Also, be able to convert between\n 68 00:06:17,990 --> 00:06:20,970 You already know that, it shouldn’t be a\nproblem. 69 00:06:20,970 --> 00:06:25,670 If it is a problem, go back and watch the\n 70 00:06:26,959 --> 00:06:32,219 If you can do those two things, convert between\n 71 00:06:32,220 --> 00:06:37,300 between decimal and binary, you’ll have\n 72 00:06:38,720 --> 00:06:42,530 Let’s walk through some conversions. 73 00:06:42,529 --> 00:06:47,599 Binary 1101 1011 is equal to what in hexadecimal? 74 00:06:50,600 --> 00:06:54,460 Remember, each hexadecimal digit contains\n4 bits of information. 75 00:06:54,459 --> 00:07:00,159 So, split the number into 4-bit groups, 1101\nand 1011. 76 00:07:00,160 --> 00:07:04,090 Then, convert each of those 4-bit groups to\ndecimal. 77 00:07:04,089 --> 00:07:08,539 1101 is 8 plus 4 plus 1, so 13. 78 00:07:08,540 --> 00:07:13,310 1011 is 8 plus 2 plus 1, so 11. 79 00:07:13,310 --> 00:07:16,280 Then convert those decimal numbers to hexadecimal. 80 00:07:16,279 --> 00:07:18,099 You should have these conversions memorized. 81 00:07:18,100 --> 00:07:24,540 13 is D, and 11 is B. Simply put those two\n 82 00:07:26,240 --> 00:07:31,870 Binary 1101 1011 is equal to hexadecimal DB. 83 00:07:31,870 --> 00:07:34,470 To check, you can use a calculator. 84 00:07:34,470 --> 00:07:40,100 For example, from the Windows 10 calculator\n 85 00:07:40,100 --> 00:07:42,670 select the programmer calculator. 86 00:07:42,670 --> 00:07:48,001 In the programmer calculator, you can select\n 87 00:07:50,449 --> 00:07:54,699 I selected hexadecimal and typed in DB. 88 00:07:54,699 --> 00:08:00,019 As you can see, it is equal to binary 1101\n1011. 89 00:08:00,019 --> 00:08:04,549 If you don’t use windows 10, your calculator\n 90 00:08:05,550 --> 00:08:11,780 Or, you can just do a Google search for a\n 91 00:08:11,779 --> 00:08:15,839 In the real world, you’d use a calculator\n 92 00:08:16,839 --> 00:08:21,049 However, it’s important to be able to do\n 93 00:08:21,050 --> 00:08:23,009 actually understand the concepts. 94 00:08:23,009 --> 00:08:28,500 Let’s do a few more practice questions for\n 95 00:08:28,500 --> 00:08:36,282 Pause the video to try this one out yourself,\n 96 00:08:38,059 --> 00:08:41,129 First split the number into 4-bit groups. 97 00:08:43,250 --> 00:08:45,730 Convert each decimal number to hexadecimal. 98 00:08:45,730 --> 00:08:53,370 And there’s the answer, binary 0010 1111\n 99 00:08:53,370 --> 00:08:57,490 We’ll do one more for binary to hex. 100 00:08:57,490 --> 00:09:00,399 Pause the video to try it out. 101 00:09:04,509 --> 00:09:07,339 First split the number into 4-bit groups. 102 00:09:07,339 --> 00:09:09,430 Convert each group to decimal. 103 00:09:09,429 --> 00:09:11,899 Convert each decimal number to hexadecimal. 104 00:09:11,899 --> 00:09:21,309 And there’s the answer, binary 1000 0001\n 105 00:09:21,309 --> 00:09:23,729 How about converting from hexadecimal to binary? 106 00:09:23,730 --> 00:09:27,519 Basically, it’s just the reverse process. 107 00:09:27,519 --> 00:09:30,399 Convert to decimal, then to binary. 108 00:09:30,399 --> 00:09:34,789 For example, what’s hexadecimal EC in binary? 109 00:09:34,789 --> 00:09:38,559 First, split up the hexadecimal digits. 110 00:09:43,750 --> 00:09:46,818 Then convert each decimal number to binary. 111 00:09:46,818 --> 00:09:53,039 And that’s the answer, hexadecimal EC is\n 112 00:09:56,870 --> 00:10:03,938 Pause the video to try it out yourself, convert\n 113 00:10:05,230 --> 00:10:08,619 First, split up the hexadecimal digits. 114 00:10:08,619 --> 00:10:10,700 Then convert them to decimal. 115 00:10:13,828 --> 00:10:16,259 Then convert each decimal number to binary. 116 00:10:16,259 --> 00:10:25,692 And that’s the answer, hexadecimal 2B is\n 117 00:10:27,149 --> 00:10:34,914 Pause the video to try it out yourself, convert\n 118 00:10:36,169 --> 00:10:40,000 First, split up the hexadecimal digits. 119 00:10:45,429 --> 00:10:48,109 Then convert each decimal number to binary. 120 00:10:48,110 --> 00:10:56,577 And that’s the answer, hexadecimal D7 is\n 121 00:10:56,577 --> 00:11:01,169 Okay, that’s all for the conversion practice,\n 122 00:11:01,169 --> 00:11:05,568 If you don’t feel comfortable converting\n 123 00:11:05,568 --> 00:11:09,969 Write out a random 8-bit, 1-byte, number and\n 124 00:11:12,958 --> 00:11:16,399 Also try it with numbers that aren’t 8 bits,\n 125 00:11:16,399 --> 00:11:20,970 Now, let’s move on to the next topic. 126 00:11:20,970 --> 00:11:25,129 And the next topic is this, ‘Why IPv6’? 127 00:11:25,129 --> 00:11:29,999 The main reason is that there simply aren’t\n 128 00:11:29,999 --> 00:11:32,449 How many IPv4 addresses are there? 129 00:11:32,448 --> 00:11:40,740 An IPv4 address is 32 bits long, so that means\n 130 00:11:44,539 --> 00:11:49,278 That may seem like a lot, but in our modern\n 131 00:11:51,419 --> 00:11:56,099 When IPv4 was being designed 30 years ago,\n 132 00:11:56,100 --> 00:12:01,540 be as large as it is today, they thought 32\n 133 00:12:01,539 --> 00:12:07,370 However, we have known about the IPv4 address\n 134 00:12:07,370 --> 00:12:10,938 techniques have been used to preserve the\nspace. 135 00:12:10,938 --> 00:12:16,610 VLSM, variable-length subnet masks is one\n 136 00:12:19,458 --> 00:12:24,388 Private IPv4 addresses and NAT, Network Address\n 137 00:12:26,909 --> 00:12:30,370 Both of those will be covered soon in the\ncourse. 138 00:12:30,370 --> 00:12:34,789 Those techniques have been very useful in\n 139 00:12:34,789 --> 00:12:37,599 they are just short-term solutions. 140 00:12:37,600 --> 00:12:43,509 The long-term solution is to transition to\nIPv6. 141 00:12:43,509 --> 00:12:47,470 Let me briefly explain how IPv4 addresses\nare assigned. 142 00:12:47,470 --> 00:12:53,060 IPv4 address assignments are controlled by\n 143 00:12:53,059 --> 00:12:58,198 I mentioned IANA in the last video about TCP\nand UDP, also. 144 00:12:58,198 --> 00:13:04,600 IANA distributes IPv4 address space to various\n 145 00:13:04,600 --> 00:13:07,740 then assign them to companies that need them. 146 00:13:07,740 --> 00:13:12,999 For example, an Internet service provider\n 147 00:13:12,999 --> 00:13:16,360 which can then be used by its customers. 148 00:13:16,360 --> 00:13:19,139 This is a map showing the various RIRs. 149 00:13:19,139 --> 00:13:24,509 To be honest, I don’t know the proper pronunciation\n 150 00:13:24,509 --> 00:13:31,669 Africa, APNIC controls Asia-Pacific, ARIN\n 151 00:13:31,669 --> 00:13:38,219 Atlantic islands, and the US, LACNIC controls\n 152 00:13:38,220 --> 00:13:42,000 NCC controls Europe, the Middle East, and\nparts of Central Asia. 153 00:13:42,000 --> 00:13:45,429 However, these RIRs are almost all out of\nIPv4 addresses. 154 00:13:45,429 --> 00:13:52,688 For example, in September 2015 ARIN declared\n 155 00:13:52,688 --> 00:13:57,419 They don’t have any more addresses to assign,\n 156 00:13:57,419 --> 00:14:00,490 ARIN can reclaim their addresses, for example. 157 00:14:00,490 --> 00:14:07,778 Here’s another one, in August 2020, LACNIC\n 158 00:14:08,828 --> 00:14:11,698 The other RIRs have similar problems, too. 159 00:14:11,698 --> 00:14:16,948 So, as you can see the situation is pretty\n 160 00:14:18,929 --> 00:14:23,079 We need something capable of supporting our\n 161 00:14:26,318 --> 00:14:30,299 Let’s finally get into the specifics. 162 00:14:30,299 --> 00:14:35,708 There is actually a lot of interesting history\n 163 00:14:37,509 --> 00:14:41,519 I think you can see why we need to transition\nto IPv6. 164 00:14:41,519 --> 00:14:46,539 If you want to read a little about it, search\n 165 00:14:53,318 --> 00:14:59,659 That’s 4 times the number of bits in an\n 166 00:14:59,659 --> 00:15:03,958 At first, you might think that 4 times the\n 167 00:15:06,789 --> 00:15:11,278 Every additional bit DOUBLES the number of\npossible addresses. 168 00:15:11,278 --> 00:15:15,088 32 bits allows for about 4 billion addresses. 169 00:15:15,089 --> 00:15:21,829 33 bits would allow about 8 billion, 34 bits\n 170 00:15:21,828 --> 00:15:26,138 So, how many IPv6 addresses are there? 171 00:15:26,139 --> 00:15:35,240 There are 340 undecillion, 282 decillion,\n 172 00:15:35,240 --> 00:15:45,275 463 sextillion, 463 quintillion, 374 quadrillion,\n 173 00:15:45,275 --> 00:15:50,556 thousand and 456 IPv6 addresses. 174 00:15:50,557 --> 00:15:54,318 Yes, I had to search on Google to learn how\nto say that number. 175 00:15:54,318 --> 00:15:57,229 But no, you don’t have to memorize it. 176 00:15:57,230 --> 00:16:01,310 For comparison, here’s the number of IPv4\naddresses again. 177 00:16:01,309 --> 00:16:05,498 Here’s an example IPv6 address in binary. 178 00:16:08,379 --> 00:16:12,860 If you write that in dotted decimal like an\n 179 00:16:12,860 --> 00:16:18,240 However, as I’ve already said Ipv6 addresses\n 180 00:16:19,769 --> 00:16:22,919 Here’s that same address written in hexadecimal. 181 00:16:22,919 --> 00:16:30,289 An IPv6 address is 128 bits, and as I said\n 182 00:16:34,438 --> 00:16:42,088 So, an IPv6 address is written as 32 hexadecimal\n 183 00:16:43,899 --> 00:16:48,759 This is still longer and more difficult to\n 184 00:16:50,360 --> 00:16:56,169 There is 4 times the amount of information\n 185 00:16:58,139 --> 00:17:03,500 IPv6 addresses use the ‘slash’ notation\n 186 00:17:03,500 --> 00:17:06,599 the address in the Cisco IOS CLI. 187 00:17:06,599 --> 00:17:09,578 No more dotted decimal subnet masks. 188 00:17:09,578 --> 00:17:15,028 This /64, for example, means the first half\n 189 00:17:15,028 --> 00:17:17,750 and the second half would be the host portion. 190 00:17:17,750 --> 00:17:23,578 In addition, there are a couple methods to\n 191 00:17:23,578 --> 00:17:29,009 Let’s look at those methods to shorten IPv6\naddresses. 192 00:17:29,009 --> 00:17:32,220 First up, leading 0s can be removed. 193 00:17:34,619 --> 00:17:41,500 ‘Leading 0s’ are any 0s at the beginning\n 194 00:17:41,500 --> 00:17:43,538 These are the leading 0s in this address. 195 00:17:43,538 --> 00:17:46,500 So, we can simply remove them. 196 00:17:46,500 --> 00:17:48,369 Now the address can be written like this. 197 00:17:48,369 --> 00:17:52,859 The 0s are still part of the address, but\n 198 00:17:54,119 --> 00:17:59,668 Okay, there’s one more technique to shorten\nan IPv6 address. 199 00:17:59,669 --> 00:18:04,059 Consecutive quartets of all 0s can be replaced\n 200 00:18:04,058 --> 00:18:09,359 For example in the address below, there are\n 201 00:18:09,359 --> 00:18:14,000 You can shorten the address like this, replacing\n 202 00:18:15,579 --> 00:18:20,250 It’s because we know an IPv6 address is\n8 quartets in length. 203 00:18:20,250 --> 00:18:24,960 We can only see four quartets now, so we know\n 204 00:18:28,890 --> 00:18:34,549 You can combine both methods, removing leading\n 205 00:18:34,548 --> 00:18:37,089 Now this address looks much easier to handle. 206 00:18:37,089 --> 00:18:40,428 But, there’s a limitation here. 207 00:18:40,429 --> 00:18:45,759 Consecutive quartets of 0s can only be abbreviated\n 208 00:18:46,759 --> 00:18:49,140 Well, look at this address here. 209 00:18:49,140 --> 00:18:51,500 You might try to shorten it like this. 210 00:18:53,159 --> 00:18:58,010 We know there should be 8 quartets in total,\n 211 00:18:58,009 --> 00:19:00,339 But how many quartets of 0s are here? 212 00:19:04,730 --> 00:19:09,169 Maybe there are 2 quartets on the left and\n 213 00:19:10,429 --> 00:19:16,309 So, this is why we can only abbreviate the\n 214 00:19:16,308 --> 00:19:19,829 Instead, we should shorten the address like\nthis. 215 00:19:19,829 --> 00:19:25,389 The left side has three all-0 quartets, so\n 216 00:19:25,390 --> 00:19:31,460 On the right side, which has two all-0 quartets,\n 217 00:19:31,460 --> 00:19:36,850 Here’s a few questions to practice shortening\nIPv6 addresses. 218 00:19:36,849 --> 00:19:39,990 Pause the video and try to complete each. 219 00:19:42,859 --> 00:19:48,269 Here’s the first one, you’re able to remove\n 220 00:19:49,750 --> 00:19:53,929 Note that there are two sets of consecutive\n 221 00:19:57,420 --> 00:20:02,730 Like the previous two, you’re able to remove\n 222 00:20:03,839 --> 00:20:07,538 There are some leading 0s you can remove in\n 223 00:20:10,339 --> 00:20:15,798 You’re able to replace five quartets of\n 224 00:20:15,798 --> 00:20:21,250 You should also be able to take a shortened\n 225 00:20:22,250 --> 00:20:24,440 Here’s an example of how to do that. 226 00:20:24,440 --> 00:20:29,940 First, put leading 0s where needed, remember\n 227 00:20:29,940 --> 00:20:34,000 characters, that’s why they’re called\nquartets. 228 00:20:34,000 --> 00:20:37,740 Where can we put leading 0s in this example\nshortened address? 229 00:20:39,460 --> 00:20:41,558 So, now the address looks like this. 230 00:20:43,900 --> 00:20:48,390 If a double colon is used, we should replace\n 231 00:20:50,769 --> 00:20:54,889 There is a double colon here, so we can expand\n 232 00:20:58,429 --> 00:21:01,860 Actually there are 8, but currently only 5\nare written. 233 00:21:01,859 --> 00:21:07,500 To make 8 total quartets, simply add three\nquartets of 0s. 234 00:21:07,500 --> 00:21:12,019 Here are a few practice questions for expanding\n 235 00:21:12,019 --> 00:21:15,058 Pause the video to solve them. 236 00:21:25,019 --> 00:21:30,548 I will talk about different IPv6 address types\n 237 00:21:30,548 --> 00:21:32,829 is a different type of address. 238 00:21:32,829 --> 00:21:38,599 IPv4 has different kinds of addresses like\n 239 00:21:40,849 --> 00:21:44,949 But as I said, that’s a topic for another\nvideo. 240 00:21:44,950 --> 00:21:49,890 Next up, let’s see how to find the IPv6\n 241 00:21:51,230 --> 00:21:54,759 We’ve already done this before for IPv4. 242 00:21:54,759 --> 00:21:58,710 Change all of the host bits to 0, and then\n 243 00:21:58,710 --> 00:22:01,759 But let’s try it out for IPv6. 244 00:22:01,759 --> 00:22:09,400 Typically, an enterprise requesting IPv6 addresses\n 245 00:22:09,400 --> 00:22:14,580 Also, typically IPv6 subnets use a /64 prefix\nlength. 246 00:22:14,579 --> 00:22:22,158 So, the enterprise received a /48 block, but\n 247 00:22:22,159 --> 00:22:26,990 This means that an enterprise has 16 bits\n 248 00:22:26,990 --> 00:22:30,388 And the remaining 64 bits can be used for\nhosts. 249 00:22:30,388 --> 00:22:32,408 I think an example will make this clearer. 250 00:22:35,210 --> 00:22:41,100 This part in blue is the /48 block assigned\n 251 00:22:42,779 --> 00:22:47,788 Note that this example is for the IPv6 ‘global\n 252 00:22:47,788 --> 00:22:52,028 As I said before, there are multiple IPv6\n 253 00:22:53,028 --> 00:22:57,160 But these ‘global unicast’ addresses are\n 254 00:22:57,160 --> 00:23:02,808 use over the Internet, they aren’t private\n 255 00:23:02,808 --> 00:23:09,470 Okay, the next 16 bits, 4 hex digits, are\n 256 00:23:09,470 --> 00:23:15,200 Because the enterprise received a /48 block\n 257 00:23:15,200 --> 00:23:21,090 a /64 prefix length, these 16 bits are free\n 258 00:23:21,089 --> 00:23:26,490 Together, these two parts make the ‘network\n 259 00:23:27,490 --> 00:23:31,359 Then the last 64 bits are the host bits. 260 00:23:31,359 --> 00:23:35,479 That is a huge amount of hosts per subnet,\n 261 00:23:35,480 --> 00:23:39,259 But the convention is to use a /64 prefix\nlength. 262 00:23:39,259 --> 00:23:43,710 However, that doesn’t mean you’ll only\n 263 00:23:43,710 --> 00:23:49,840 So, we’ll practice using IPv6 addresses\n 264 00:23:49,839 --> 00:23:55,099 Finding the prefix of an IPv6 address with\n 265 00:23:55,099 --> 00:23:57,519 Simply make the second half of the address\nall 0s. 266 00:23:57,519 --> 00:24:02,980 That’s what I did here, and notice I shortened\n 267 00:24:02,980 --> 00:24:08,159 the host portion, which is all 0s, with a\ndouble colon. 268 00:24:08,159 --> 00:24:13,309 Even if the prefix length isn’t /64, if\n 269 00:24:13,308 --> 00:24:15,528 easy to find the prefix length. 270 00:24:16,528 --> 00:24:20,609 It’s because each hexadecimal character\nis 4 bits. 271 00:24:20,609 --> 00:24:27,469 56 is a multiple of 4, so let me show you\n 272 00:24:27,470 --> 00:24:31,250 This first quartet is the first 16 bits of\nthe address. 273 00:24:31,250 --> 00:24:33,579 This one brings it to 32 bits. 274 00:24:35,259 --> 00:24:38,720 This 2 contains the next 4 bits, so 52. 275 00:24:38,720 --> 00:24:42,259 And this 1 contains another 4 bits, so 56\nbits. 276 00:24:42,259 --> 00:24:48,058 So, these first 14 characters are the network\n 277 00:24:48,058 --> 00:24:54,210 Everything after is the host portion, so we\n 278 00:24:54,210 --> 00:24:58,970 Here it is, after removing leading 0s and\n 279 00:24:58,970 --> 00:25:02,000 Let me point out that you can’t remove these\n0s. 280 00:25:02,000 --> 00:25:05,980 Even though they are part of the host portion\n 281 00:25:07,940 --> 00:25:13,009 For example, if you were to shorten the address\n 282 00:25:13,009 --> 00:25:18,048 the leading 0s back the prefix would be this,\n 283 00:25:19,638 --> 00:25:24,139 So, remember that point, you can only remove\nthe ‘leading’ 0s. 284 00:25:27,589 --> 00:25:31,548 Find where the network portion ends, and change\n 285 00:25:31,548 --> 00:25:36,778 But with an IPv6 address like this you need\n 286 00:25:36,778 --> 00:25:41,058 The prefix length is /93, which isn’t a\nmultiple of 4. 287 00:25:41,058 --> 00:25:46,529 So, that means that the network portions ends\n 288 00:25:48,079 --> 00:25:59,220 16 bits, 32 bits, 48 bits, 64 bits, 80 bits,\n 289 00:26:00,220 --> 00:26:05,558 So, the network portion includes all of these\n 290 00:26:05,558 --> 00:26:12,548 So, in order to properly write out the network\n 291 00:26:12,548 --> 00:26:17,329 As you know, hexadecimal B is equal to decimal\n11. 292 00:26:17,329 --> 00:26:21,480 Decimal 11 is written as 1011 in binary. 293 00:26:21,480 --> 00:26:25,591 Only this first bit is part of the network\n 294 00:26:31,180 --> 00:26:33,380 Change that back to decimal, which is 8. 295 00:26:33,380 --> 00:26:35,528 It’s also written as 8 in hexadecimal. 296 00:26:35,528 --> 00:26:41,470 So, when we write out the network prefix,\n 297 00:26:41,470 --> 00:26:43,669 because we changed the host bits all to 0. 298 00:26:43,669 --> 00:26:46,740 So, here’s the network prefix. 299 00:26:46,740 --> 00:26:49,470 Notice the ‘8’ instead of the ‘B’. 300 00:26:49,470 --> 00:26:53,190 I hope you can see the importance of really\n 301 00:26:53,190 --> 00:26:57,049 If you don’t know binary, it would be tough\n 302 00:26:57,049 --> 00:26:59,970 all of the host bits are changed to 0. 303 00:27:01,898 --> 00:27:07,719 If you don’t know binary, you can’t really\n 304 00:27:07,720 --> 00:27:12,970 Here are some practice questions, find the\n 305 00:27:12,970 --> 00:27:16,569 Pause the video now to do that. 306 00:27:25,798 --> 00:27:28,980 Note that you don’t have to write out the\n 307 00:27:31,259 --> 00:27:35,639 If you still want some more practice, try\n 308 00:27:35,638 --> 00:27:40,990 random prefix lengths yourself, and then try\n 309 00:27:40,990 --> 00:27:48,630 So, we’ve only covered the absolute basics\n 310 00:27:48,630 --> 00:27:52,790 But I want to include a lab with each lecture\n 311 00:27:52,789 --> 00:27:55,519 some very basic IPv6 configuration. 312 00:27:55,519 --> 00:28:00,679 I’ll just show you how to configure IPv6\n 313 00:28:00,679 --> 00:28:03,298 the next video you can try it out in Packet\nTracer. 314 00:28:03,298 --> 00:28:09,970 So, R1 has three interfaces, each connected\n 315 00:28:09,970 --> 00:28:22,139 2001:db8:0:0::/64 on the G0/0 interface, 0:1::/64\n 316 00:28:22,138 --> 00:28:26,658 In this example, the company was assigned\n 317 00:28:26,659 --> 00:28:30,809 quartet of the prefix to make different subnets. 318 00:28:30,808 --> 00:28:36,548 Just a side point, you may be wondering why\n 319 00:28:36,548 --> 00:28:43,450 That’s because this range of IPv6 addresses\n 320 00:28:43,450 --> 00:28:46,960 They should never actually be used in real\n 321 00:28:52,210 --> 00:28:56,169 First up, you have to use the command IPV6\nUNICAST-ROUTING. 322 00:28:56,169 --> 00:28:59,759 This command allows the routers to perform\nIPv6 routing. 323 00:28:59,759 --> 00:29:05,089 If you don’t enable this, it’s not going\n 324 00:29:05,089 --> 00:29:08,470 Next up, I configured the G0/0 interface. 325 00:29:08,470 --> 00:29:14,899 The command to configure an IPv6 address is\n 326 00:29:15,980 --> 00:29:21,750 You’ll notice that a lot of IPv6 commands\n 327 00:29:25,700 --> 00:29:29,569 Also notice that you can use the shortened\n 328 00:29:31,599 --> 00:29:35,339 Remember to use NO SHUTDOWN to enable the\ninterface, too. 329 00:29:35,339 --> 00:29:42,379 I did the same thing on G0/1, and then G0/2,\n 330 00:29:42,380 --> 00:29:46,990 You can use the whole address, the shortened\n 331 00:29:46,990 --> 00:29:51,220 the router will understand what you mean. 332 00:29:51,220 --> 00:29:52,649 Now let’s confirm the configurations. 333 00:29:52,648 --> 00:29:56,919 I used the command SHOW IPV6 INTERFACE BRIEF. 334 00:29:56,920 --> 00:30:02,990 Again, same as the IPv4 command, you just\nhave to use ‘IPv6’. 335 00:30:02,990 --> 00:30:05,970 There are a few things to point out here. 336 00:30:05,970 --> 00:30:10,700 First up, notice that the shortened version\n 337 00:30:11,778 --> 00:30:16,929 Actually, the address on the G0/0 interface\n 338 00:30:19,099 --> 00:30:23,709 To emphasize that the first four quartets\n 339 00:30:23,710 --> 00:30:28,429 two 0s here in the network diagram and when\n 340 00:30:28,429 --> 00:30:32,000 But they can be included in the double colon\n 341 00:30:33,500 --> 00:30:39,339 Okay, next thing to point out, something you\n 342 00:30:39,339 --> 00:30:44,769 has two IPv6 addresses, even though we only\nconfigured one. 343 00:30:44,769 --> 00:30:48,740 These are called ‘link-local’ addresses,\n 344 00:30:48,740 --> 00:30:55,140 interface when you configure an IPv6 address,\n 345 00:30:55,140 --> 00:31:00,630 I will cover these in Day 32 when I cover\n 346 00:31:00,630 --> 00:31:04,990 want to read about them before that Wikipedia\n 347 00:31:04,990 --> 00:31:10,579 IPv4 has link-local addresses as well, although\n 348 00:31:11,579 --> 00:31:16,869 Anyway, as I said I’ll cover those in Day\n32. 349 00:31:16,869 --> 00:31:21,388 Before moving on to the quiz let’s review\n 350 00:31:21,388 --> 00:31:26,168 First up we reviewed hexadecimal and practiced\n 351 00:31:26,169 --> 00:31:30,909 Although we briefly covered hexadecimal when\n 352 00:31:30,909 --> 00:31:34,169 even more important to be comfortable with\nit. 353 00:31:34,169 --> 00:31:37,299 Then I introduced why IPv6 is necessary. 354 00:31:37,298 --> 00:31:41,589 Basically, there aren’t enough IPv4 addresses\n 355 00:31:41,589 --> 00:31:48,109 I covered the basics of IPv6, and the main\n 356 00:31:48,109 --> 00:31:53,658 which are 128-bits in length and usually written\n 357 00:31:53,659 --> 00:31:57,789 Finally I showed you the basic commands to\n 358 00:31:57,788 --> 00:32:00,819 IPv6 addresses on an interface. 359 00:32:00,819 --> 00:32:05,028 There is still a lot more that we have to\n 360 00:32:07,048 --> 00:32:11,079 Make to sure watch until the end of the quiz\n 361 00:32:11,079 --> 00:32:13,388 best practice exams for the CCNA. 362 00:32:13,388 --> 00:32:18,849 They’re the practice exams I used to prepare\n 363 00:32:20,650 --> 00:32:23,750 If you want to get ExSim, follow the link\n 364 00:32:23,750 --> 00:32:29,638 Okay, let’s move on to question 1 of the\nquiz. 365 00:32:29,638 --> 00:32:32,648 Which of the following are valid IPv6 addresses? 366 00:32:35,859 --> 00:32:41,979 Pause the video now to find the answers, only\n 367 00:32:41,980 --> 00:32:46,288 Okay, let’s check the answers. 368 00:32:46,288 --> 00:32:52,648 The valid IPv6 addresses are A, B, and E.\nWhy is C invalid? 369 00:32:52,648 --> 00:32:55,028 It has a G in the fourth quartet. 370 00:32:55,028 --> 00:33:02,759 IPv6 addresses use hexadecimal, which only\n 371 00:33:06,099 --> 00:33:11,699 An IPv6 address should have only 8 quartets\n 372 00:33:14,528 --> 00:33:16,769 It’s using the double colon twice. 373 00:33:16,769 --> 00:33:21,119 Remember, you can only use the double colon\n 374 00:33:21,119 --> 00:33:24,648 Okay, let’s go to question 2. 375 00:33:24,648 --> 00:33:30,339 Which of the following is a correctly-abbreviated\n 376 00:33:32,169 --> 00:33:38,080 Pause the video now to select the correct\none. 377 00:33:38,079 --> 00:33:44,349 The correct answer is D. All of these abbreviations\n 378 00:33:44,349 --> 00:33:49,638 can only remove ‘leading’ 0s from an IPv6\n 379 00:33:50,950 --> 00:33:54,569 So, only D is a correct abbreviation of the\naddress. 380 00:33:57,638 --> 00:34:02,569 Which of the following commands must be used\n 381 00:34:02,569 --> 00:34:06,788 A, IPV6 UNICAST-ROUTING from interface config\nmode. 382 00:34:06,788 --> 00:34:10,579 B, IPV6 UNICAST-ROUTING from global config\nmode. 383 00:34:10,579 --> 00:34:14,390 C, IPV6 ROUTING from global config mode. 384 00:34:14,389 --> 00:34:18,210 Or D, IPV6 ROUTING from interface config mode. 385 00:34:18,210 --> 00:34:25,059 Pause the video to think about your answer. 386 00:34:25,059 --> 00:34:30,889 The answer is B. IPV6 UNICAST-ROUTING, entered\n 387 00:34:30,889 --> 00:34:33,260 the router to perform IPv6 routing. 388 00:34:33,260 --> 00:34:38,409 Okay, we had lots of practice questions earlier\n 389 00:34:38,409 --> 00:34:42,240 Now let’s do a bonus question from Boson\nExSim for CCNA. 390 00:34:42,239 --> 00:34:47,848 Okay, here's today's Boson ExSim practice\nquestion. 391 00:34:47,849 --> 00:34:51,510 This question actually covers something we\n 392 00:34:54,418 --> 00:34:58,879 What command would you issue on RouterA so\n 393 00:34:59,880 --> 00:35:04,369 So, this is a question about static routing\nusing IPv6. 394 00:35:04,369 --> 00:35:10,329 However, the IPv6 static route command is\n 395 00:35:10,329 --> 00:35:13,869 Like I said in the video, a lot of IPv6 commands\nare like that. 396 00:35:13,869 --> 00:35:18,730 The only difference is instead of IP ROUTE\nit's IPV6 ROUTE. 397 00:35:18,730 --> 00:35:25,010 So, the command is IPV6 ROUTE, followed by\n 398 00:35:25,010 --> 00:35:28,270 and the prefix length here, and then the next\nhop. 399 00:35:28,269 --> 00:35:31,239 Okay, so that's the IPv6 static route command. 400 00:35:31,239 --> 00:35:35,139 So, knowing that, you should be able to answer\nthis question. 401 00:35:35,139 --> 00:35:43,411 So pause the video here and try to find the\ncorrect answer. 402 00:35:43,411 --> 00:35:45,879 Okay, hopefully you found the answer. 403 00:35:48,677 --> 00:35:55,690 So, RouterA needs to reach RouterC, which\n 404 00:35:55,690 --> 00:36:00,119 So, that should be the destination in the\nstatic route command. 405 00:36:00,119 --> 00:36:06,329 So that means the correct answer is either\n 406 00:36:06,329 --> 00:36:10,650 2001:DB8:1::/64, which is not correct. 407 00:36:10,650 --> 00:36:13,889 So, is the correct answer B or D? 408 00:36:13,889 --> 00:36:22,230 Let's see, so the next hop should be RouterB's\n 409 00:36:23,900 --> 00:36:29,170 So, which one has the correct next hop? 410 00:36:29,170 --> 00:36:35,170 This one here, B. 2001:DB8:1::2, that looks\ncorrect. 411 00:36:36,820 --> 00:36:40,910 The next hop is 2001:DB8:2::2, that is not\ncorrect. 412 00:36:40,909 --> 00:36:45,808 That would mean RouterC is the next hop, but\n 413 00:36:46,809 --> 00:36:49,470 Okay, so B should be the correct answer. 414 00:36:49,469 --> 00:36:52,299 I will click on 'show answer'. 415 00:36:54,510 --> 00:36:57,329 So here is Boson's explanation. 416 00:36:57,329 --> 00:37:00,490 You can pause the video here to read that. 417 00:37:00,489 --> 00:37:03,709 Also notice there is some Cisco documentation\nincluded. 418 00:37:03,710 --> 00:37:07,500 This is available free online and it's a great\nstudy resource. 419 00:37:07,500 --> 00:37:12,730 And also it shows you which category of the\n 420 00:37:12,730 --> 00:37:15,108 And it is from 'IP Connectivity'. 421 00:37:15,108 --> 00:37:22,690 Okay, so that is an example question from\nBoson ExSim for CCNA. 422 00:37:22,690 --> 00:37:27,550 If you're looking for CCNA practice exams,\n 423 00:37:27,550 --> 00:37:29,420 These are fantastic practice exams. 424 00:37:29,420 --> 00:37:34,630 I used them when preparing for my CCNA and\n 425 00:37:34,630 --> 00:37:42,640 If you want to get a copy of Boson ExSim,\n 426 00:37:42,639 --> 00:37:45,690 There are supplementary materials for this\nvideo. 427 00:37:45,690 --> 00:37:49,280 There is a flashcard deck to use with the\nsoftware ‘Anki’. 428 00:37:49,280 --> 00:37:53,730 There will also be a packet tracer practice\n 429 00:37:53,730 --> 00:37:56,309 That will be in the next video. 430 00:37:56,309 --> 00:37:59,650 Sign up for my mailing list via the link in\n 431 00:37:59,650 --> 00:38:04,880 the flashcards and packet tracer lab files\nfor the course. 432 00:38:04,880 --> 00:38:09,550 Before finishing today’s video I want to\n 433 00:38:09,550 --> 00:38:13,940 To join, please click the ‘Join’ button\nunder the video. 434 00:38:13,940 --> 00:38:18,960 Thank you to Magrathea, Njabulo, Benjamin,\n 435 00:38:18,960 --> 00:38:26,000 Nil, Prakaash, Nasir, Erlison, Apogee, Wasseem,\n 436 00:38:26,000 --> 00:38:32,449 Samil, Ed, Value, John, Funnydart, Scott,\n 437 00:38:32,449 --> 00:38:40,489 C Mohd, Johan, Mark, Yousif, Sidi, Boson Software,\n 438 00:38:40,489 --> 00:38:45,699 Sorry if I pronounced your name incorrectly,\n 439 00:38:45,699 --> 00:38:49,929 One of you is still displaying as Channel\n 440 00:38:49,929 --> 00:38:52,669 me know and I’ll see if YouTube can fix\nit. 441 00:38:52,670 --> 00:38:57,159 This is the list of JCNP-level members at\n 442 00:38:57,159 --> 00:39:02,019 8th 2020, if you signed up recently and your\n 443 00:39:06,449 --> 00:39:10,429 Please subscribe to the channel, like the\n 444 00:39:10,429 --> 00:39:13,699 with anyone else studying for the CCNA. 445 00:39:13,699 --> 00:39:16,519 If you want to leave a tip, check the links\nin the description. 446 00:39:16,519 --> 00:39:23,019 I'm also a Brave verified publisher and accept\n 36418

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