All language subtitles for 27. Extra Recursion 4 - Find if Digits are Ascending, Descending, or not - Question

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These are the user uploaded subtitles that are being translated: 1 00:00:00,880 --> 00:00:01,750 All right. 2 00:00:01,850 --> 00:00:07,750 What is going on, ladies and gentlemen, and welcome to this video where we are going to develop a 3 00:00:07,750 --> 00:00:11,390 recursive function that receives an integer number. 4 00:00:11,650 --> 00:00:13,930 OK, so we are going to do some recursion. 5 00:00:15,100 --> 00:00:22,810 Another exercise and you are going to become even better and you will get more knowledge and more experience 6 00:00:22,810 --> 00:00:24,730 working with recursion. 7 00:00:25,480 --> 00:00:31,180 So what do you have to do is to develop a recursive function that receives an integer number and all 8 00:00:31,180 --> 00:00:36,250 the functions you do is it should observe the digits from left to right. 9 00:00:36,580 --> 00:00:42,850 And then based on the order of these digits, the function should return one. 10 00:00:43,270 --> 00:00:51,370 If the digits from left to right are very ascending, the function should return minus one if the digits 11 00:00:51,370 --> 00:00:54,130 from left to right are very descending. 12 00:00:55,090 --> 00:00:57,280 And the function should return is zero. 13 00:00:57,430 --> 00:00:58,270 Otherwise. 14 00:00:58,810 --> 00:01:05,890 So simply saying we look at the digits from left right and we say if they are incrementing from left 15 00:01:05,890 --> 00:01:11,120 to right, we will return one if they are a discriminating from left to right. 16 00:01:11,140 --> 00:01:12,700 We will return minus one. 17 00:01:13,090 --> 00:01:21,340 And if we have any other case, like if maybe two digits are the same or basically if two digits, we 18 00:01:21,340 --> 00:01:27,100 have one digits smaller than the other and then we have another digit smaller than this one. 19 00:01:27,310 --> 00:01:32,150 Then basically, we can say that it's definitely not very ascending, neither. 20 00:01:32,230 --> 00:01:38,170 It's also not a very descending a sequence of digits. 21 00:01:38,470 --> 00:01:38,830 OK. 22 00:01:39,820 --> 00:01:40,180 So. 23 00:01:41,400 --> 00:01:48,030 We know that this exercise can be easily solved just by using some loops, right, we can use some loop 24 00:01:48,030 --> 00:01:51,180 iterating over each and every one of the digits. 25 00:01:51,660 --> 00:01:58,050 Probably we will do also the same here, but for now, because we are requested to develop a function, 26 00:01:58,050 --> 00:01:59,550 a recursive function. 27 00:01:59,910 --> 00:02:04,170 We will say, at least at the beginning, we will say, OK, we have. 28 00:02:05,110 --> 00:02:11,700 First, the idea of using loops, let's take loops, put them aside and try to solve it in another way, 29 00:02:11,710 --> 00:02:13,330 in a recursive manner. 30 00:02:13,540 --> 00:02:22,120 When we are going to take a bigger problem, splitting it up to smaller problems, some problems in 31 00:02:22,130 --> 00:02:25,230 making conclusions based on this day vision. 32 00:02:25,640 --> 00:02:29,170 OK, that's what we are requested to do to write the recursive function. 33 00:02:30,160 --> 00:02:36,280 Also, a couple of assumptions that we need to take into account is, first of all, that we can take 34 00:02:36,280 --> 00:02:43,060 some assumption that the initial noun verb to function is going to receive is basically has more than 35 00:02:43,060 --> 00:02:44,860 two digits, two digits and beyond. 36 00:02:44,860 --> 00:02:49,120 OK, it's not just one one digit number. 37 00:02:49,420 --> 00:02:53,740 If it was like if we had to take into consideration all the possibilities. 38 00:02:54,010 --> 00:03:00,280 So basically just there were a couple of few changes that we would need to add. 39 00:03:00,460 --> 00:03:07,570 But for now, we will assume that our now is at least of two digit size and all digits in some are different. 40 00:03:07,720 --> 00:03:08,110 OK. 41 00:03:08,140 --> 00:03:14,860 That's very important to take into account because if not, we would need to add a few more lines of 42 00:03:14,860 --> 00:03:15,220 code. 43 00:03:15,730 --> 00:03:21,610 That's basically something that we can do, but for now, that will be sufficient for us to work and 44 00:03:21,610 --> 00:03:26,840 to develop these recursive function with these pretty much nice assumptions. 45 00:03:26,860 --> 00:03:32,080 OK, so we have initial number of two plus digits and all digits in some are different. 46 00:03:32,110 --> 00:03:36,370 No pair of digits are the same, meaning all the digits are going to be different. 47 00:03:36,640 --> 00:03:39,460 In this example, we will simply use it like this. 48 00:03:39,550 --> 00:03:41,470 OK, so all the digits will be different. 49 00:03:41,890 --> 00:03:48,640 So for example, if we have, this number now equals two one two four, then we can say that the function 50 00:03:48,640 --> 00:03:49,720 should return one. 51 00:03:50,020 --> 00:03:56,080 Because if we take a look at the digits from left to right, we will see that the digits are very ascending. 52 00:03:56,980 --> 00:04:02,170 If we will take a look at this one, we will see that although the digits seem to be very ascending, 53 00:04:02,560 --> 00:04:04,510 the last digit is descending. 54 00:04:04,690 --> 00:04:11,830 And that means that the sequence of these digits from left to right is neither very ascending nor very 55 00:04:11,830 --> 00:04:12,460 descending. 56 00:04:13,540 --> 00:04:19,240 Final option is when, whenever we return, minus one is when we have from left to right. 57 00:04:19,450 --> 00:04:25,480 If we take a look at the digits and we see that they are very descending, meaning for every pair of 58 00:04:25,480 --> 00:04:29,890 digits that we take, the left digit will be greater than the right one. 59 00:04:30,310 --> 00:04:32,320 OK, so that's the function that you have to develop. 60 00:04:33,340 --> 00:04:35,560 Take some time to think about what should be the solution. 61 00:04:35,560 --> 00:04:37,390 How to approach this exercise. 62 00:04:37,390 --> 00:04:38,740 Write some code on your own. 63 00:04:38,740 --> 00:04:47,320 Try to run it using some function, some main call for these function and make sure that your idea works 64 00:04:47,320 --> 00:04:51,130 and then compare it with the results that we are going to do together. 6587

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