Original subtitles

All right, what is going on, ladies and gentlemen, my name is Vlad.

This is Alpha Tech Academy and we are proceeding with additional exercises in our programming course.

So this video and this exercise, what we are going what you are basically required to do is to write

a function that gets some number of an integer type and a digit.

OK, and these function that you are going to write has to do two things, OK?

The function should.

So let's say the function should know.

Let's specify what exactly each should do.

One, two.

So the function, first of all, should find out how many numbers, OK, how many?

No, let's see how many digits.

OK are less than the specified digit.

So when we are given with this number, OK with this num value and this value can be of one digit to

the five digits, seven digits and so on.

And we are interested in finding out how many digits inside of these naoum value are basically less

than these digits that was specified as the second argument for these function.

So we will need to Lizzi print.

OK, the total amount, total amount of digits in normal that are which are less than digits.

OK, is that clear so far?

And also what will will have to do is to return.

OK, we are going once again to discuss the differences between these two formulations or I don't know,

terminologies, whatever you call it.

The function should return the average the average of those digits.

OK, the average of the values of these digits that are that are less than digits.

OK, so let's see a couple of examples.

Let's say that we have, I don't know, example number one.

And then we have example number two.

So at example number one, what we have is something like this, I don't know, let's say we have a

number like one three, five and seven, OK, and one three five seven two.

That's the number that what number equals two.

So now equals to this one and digit equals two.

I don't know.

Let's see three.

And in this case we know that if we take a look, if we take a look at this number, we will see that

one is less than three.

Three is not less than three, five seven and two is less than three.

So we know that one and two are less than these value three.

So the function should print.

It should print the amount of digits, the amount of digits, which are less than digits itself.

Then in this case, we should print just two because we have two digits, less than three.

And then the value of these three major and also what these function should do is to return the average.

So if we know that one and two are basically the values that interest us, then in this case we should

return one plus two divided by two.

Right.

That's basically what should what we should return.

And in this case, it's going simply to be like to return turn one and a half.

OK, so that's basically what this function is all going to do.

If we take another example, I don't know.

Nomikos to one, two, three, one, two, three.

And digit equals digit equals to, I don't know, three once again.

Then in this case, the function is going to print what he's going to print.

One, two, one, two, four four is the total amount of digits, less than the digit three.

And the function is going to return average and its average is going to be one plus two plus one plus

two is six divided by four.

In this case, that's just what happened.

The function is also going to return one and a half.

So I hope the instructions for this exercise are basically clear.

Do you think about the signature of the of the function as well as one this function gets where it should

it print the values we are or should it return?

OK, make the distinguish and basically understand the differences between printing and returning something.

OK, I think we talked about it pretty pretty much enough.

So, yeah, so that's about these function.

Try to do your best, guys, give it a try on your own, and of course, we'll solve this exercise together

right away once you are done in our solutions.

So if you have any questions, feel free to ask them.

And until the solutions, I'll see you that.