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These are the user uploaded subtitles that are being translated: 0 00:00:00,000 --> 00:00:01,917 MICHAEL HEMANN: So what we're going to do here 1 00:00:01,917 --> 00:00:05,190 is we're going to actually use this kind of tetrad analysis 2 00:00:05,190 --> 00:00:10,620 to identify double crossovers, which we know 3 00:00:10,620 --> 00:00:17,340 are very difficult to identify in the Drosophila crosses, 4 00:00:17,340 --> 00:00:19,560 the mammalian crosses, and are going 5 00:00:19,560 --> 00:00:23,670 to be easier to identify using this tetrad analysis. 6 00:00:23,670 --> 00:00:26,530 It's really the power of this tetrad analysis. 7 00:00:26,530 --> 00:00:39,490 So we're going to use tetrad analysis to find 8 00:00:39,490 --> 00:00:49,140 hidden double crossovers. 9 00:00:49,140 --> 00:00:51,540 OK, so let's think about our initial event 10 00:00:51,540 --> 00:00:58,560 again where we have big A, big B, big A, big B going 11 00:00:58,560 --> 00:01:07,100 into meiosis, little a, little b, little a, little b. 12 00:01:07,100 --> 00:01:08,940 And let's number of these chromosomes. 13 00:01:08,940 --> 00:01:12,770 So the top is one, second is two, the third is three, 14 00:01:12,770 --> 00:01:15,820 the bottom is four. 15 00:01:15,820 --> 00:01:18,370 So let's say we have a crossover event that 16 00:01:18,370 --> 00:01:22,150 occurs between chromosomes two and three. 17 00:01:22,150 --> 00:01:33,560 So first crossover is between two and three. 18 00:01:33,560 --> 00:01:35,900 And so if you get that crossover event, 19 00:01:35,900 --> 00:01:49,015 you have AB; big A, little b; little a, big B; 20 00:01:49,015 --> 00:01:51,270 little a, little b. 21 00:01:51,270 --> 00:01:54,250 22 00:01:54,250 --> 00:01:56,770 So again, what kind of tetrad is this 23 00:01:56,770 --> 00:01:58,030 if this were the end of it? 24 00:01:58,030 --> 00:02:02,430 25 00:02:02,430 --> 00:02:07,020 T. It'd be a tetratype, so we have four different possible-- 26 00:02:07,020 --> 00:02:11,580 we have four different distinct haploid cells. 27 00:02:11,580 --> 00:02:15,010 Now let's think about a second crossover. 28 00:02:15,010 --> 00:02:16,105 So second. 29 00:02:16,105 --> 00:02:21,240 30 00:02:21,240 --> 00:02:24,030 And here we're going to have different possibilities. 31 00:02:24,030 --> 00:02:28,770 We can have a second crossover being a two, 32 00:02:28,770 --> 00:02:32,490 three crossover or it could be a one, 33 00:02:32,490 --> 00:02:42,630 four crossover or it could be a one, three crossover 34 00:02:42,630 --> 00:02:45,910 or it could be a two, four crossover. 35 00:02:45,910 --> 00:02:48,880 So we're thinking about all of the other chromosomes 36 00:02:48,880 --> 00:02:52,180 could recombine after this initial event. 37 00:02:52,180 --> 00:02:54,200 Just sort of random. 38 00:02:54,200 --> 00:02:59,260 So what if you actually had a crossover event that occurred 39 00:02:59,260 --> 00:03:05,270 again between two and three? 40 00:03:05,270 --> 00:03:07,280 What would the outcome of that crossover 41 00:03:07,280 --> 00:03:09,950 be in terms of the kind of tetrad 42 00:03:09,950 --> 00:03:12,590 that you would get in the end? 43 00:03:12,590 --> 00:03:13,160 Exactly. 44 00:03:13,160 --> 00:03:16,460 So this kind of tetrad or this kind of recombination event 45 00:03:16,460 --> 00:03:19,880 would result in a PD because all you're doing 46 00:03:19,880 --> 00:03:22,790 is flipping it back the way it came, 47 00:03:22,790 --> 00:03:25,520 so you're just restoring the initial orientation. 48 00:03:25,520 --> 00:03:27,480 So you're getting what you had to begin with, 49 00:03:27,480 --> 00:03:33,490 which is that or this, which is a parental ditype. 50 00:03:33,490 --> 00:03:35,650 All right, so let's think, OK, what 51 00:03:35,650 --> 00:03:38,980 happens if you had a crossover event that 52 00:03:38,980 --> 00:03:41,800 went between one and four? 53 00:03:41,800 --> 00:03:46,730 54 00:03:46,730 --> 00:03:52,250 So there you're putting a big B down to the bottom 55 00:03:52,250 --> 00:03:56,470 and a little b up at the top. 56 00:03:56,470 --> 00:03:57,040 Exactly. 57 00:03:57,040 --> 00:04:03,130 So this kind is a nonparental ditype 58 00:04:03,130 --> 00:04:06,400 because what you end up with is big a, little B; 59 00:04:06,400 --> 00:04:12,220 big a, little B; little a, big B; little a, big B. 60 00:04:12,220 --> 00:04:15,310 So two different types, they're either big A, little 61 00:04:15,310 --> 00:04:18,610 b or little a, big B, and neither of them 62 00:04:18,610 --> 00:04:22,480 are parental so they're nonparental ditypes. 63 00:04:22,480 --> 00:04:33,250 OK, so what happens if you get a one to three a crossover event? 64 00:04:33,250 --> 00:04:38,750 65 00:04:38,750 --> 00:04:40,430 Yep, it's tetratype. 66 00:04:40,430 --> 00:04:43,250 You notice you're not really changing much here. 67 00:04:43,250 --> 00:04:46,910 You're actually moving a big B down to a big B and a big B 68 00:04:46,910 --> 00:04:50,430 up to a big B, so you're not changing anything. 69 00:04:50,430 --> 00:04:54,020 And this initial-- this second three cross 70 00:04:54,020 --> 00:04:56,510 resulted in a tetratype, so you're just going 71 00:04:56,510 --> 00:04:59,160 to maintain that tetratype. 72 00:04:59,160 --> 00:05:04,140 You have four different kinds of haploid cells. 73 00:05:04,140 --> 00:05:05,870 And you'll notice the same thing happens 74 00:05:05,870 --> 00:05:09,320 if you recombined two and four. 75 00:05:09,320 --> 00:05:12,800 So there you're just going to bring a little b up an exchange 76 00:05:12,800 --> 00:05:15,080 with another little b. 77 00:05:15,080 --> 00:05:19,370 So again, you're going to have a tetratype 78 00:05:19,370 --> 00:05:23,990 if you do have a second two, four recombination. 79 00:05:23,990 --> 00:05:27,680 And so you can go through this looking 80 00:05:27,680 --> 00:05:30,530 at any of these different starting alleles 81 00:05:30,530 --> 00:05:34,400 and if you have a crossover event between A and B, 82 00:05:34,400 --> 00:05:37,160 regardless what chromosome they're on, 83 00:05:37,160 --> 00:05:41,990 the first crossover always generates a tetratype. 84 00:05:41,990 --> 00:05:49,100 85 00:05:49,100 --> 00:05:52,580 And again, we're talking about crossovers between homologues 86 00:05:52,580 --> 00:05:55,580 here, not crossovers between sister chromotids. 87 00:05:55,580 --> 00:06:05,336 Crossover between homologues always yields a T. 88 00:06:05,336 --> 00:06:20,280 And all of these second crossovers are equally likely, 89 00:06:20,280 --> 00:06:22,960 and you expect them to occur at this ratio. 90 00:06:22,960 --> 00:06:28,670 So one PD to one NPD to two different Ts. 6722

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