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MICHAEL HEMANN: Say you are in the lab
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and you've just identified a new strain, right?
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And so, we're going to call this strain hisX minus.
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So-- and I think this refers to a question that was put
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in the chat a little bit earlier on--
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so hisX minus is a strain that can't grow
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without exogenous histidine.
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So it's a histidine auxotroph.
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But we don't know anything about what gene
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this mutation is in, right?
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And you've just developed this in lab,
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and you've been working on his3 for a while,
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and you want to know--
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is hisX minus the same as his3 minus?
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Are they simply mutations in the same gene,
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or this represent a new gene that's mutated
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that causes the same phenotype?
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Well how do we figure this out?
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Well we figure it out by simply crossing these haploids
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together in what we'll call, essentially,
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a complementation test.
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So we're going to think, essentially,
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of two distinct possibilities.
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And the first possibility is that hisX minus
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is the same as his3 minus.
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They're essentially mutations in the same gene.
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And so in this case, the diploid genotype
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is hisX minus over his3 minus.
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Or we can write that, if they're equivalent,
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as his3 minus over his3 minus.
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And the phenotype of this, of course, is his minus.
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So if we're putting the same mutation in opposition
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to itself, we're not restoring function.
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And so we are now his minus.
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Well let's think of, then, the other possibility.
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And so the other possibility is hisX minus
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is not the same as his3 minus.
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And so the resulting diploid genotype
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is going to be hisX plus over hisX minus.
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And his3 minus over his3 plus.
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Why is that?
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Because we're dealing here with two distinct genes.
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And sort of the inferred phenotype of the haploids
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is that you are--
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if you are hisX minus, you are his3 plus.
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And we can write sort of two genes in series.
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So these are two distinct genes-- hisX minus
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and his3 plus.
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Whereas the other strain would be hisX plus and his3 minus.
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So if we're just saying that they're
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a mutant for a single gene, we're
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assuming they're wild type for all of the others.
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And so in each case, you're bringing
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a functional copy of his3 and a functional copy of hisX
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into this cross.
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And so the resulting diploid genotype
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is going to be heterozygousity for both of these genes.
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And the phenotype is going to be--
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yeah.
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So there's a question-- are we assuming
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there's only one mutation in this synthesis pathway?
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We do assume that.
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And there are, I think, important ways
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that you actually make sure that that's actually the case--
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where you actually are maintaining strains
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with the idea that there's only sort of single defects.
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Now we'll talk about this idea that maybe
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there are multiple defects--
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I think in a couple of lectures.
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But the assumption is, if I say something
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is his3 minus, that is the only mutation within this pathway.
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OK.
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So the resulting, you know, diploid in this case
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is going to be his plus.
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Because they have one functional copy of hisX,
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they have one functional copy of his3,
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these are actually compensating for the deficiency
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of each other.
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And so we're going to introduce this idea of complementation.
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And complementation essentially means that the cross between--
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or the progeny of a cross between two mutants
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is wild type.
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Or haploids, or diploids, that have a mutant phenotype
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yields a wild type phenotype.
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So can you actually restore the function of the gene
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deficiency in the other strain?
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Can two strains that separately have
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a problem, or a phenotypic problem,
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restore function in that pathway?
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So if you have mutations in this same gene,
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you do not complement.
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If you have mutations in different genes,
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you do complement.
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So if you have a study group and you
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and your friend know exactly half of the material,
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but you know same half of the material,
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you're not actually complementing one another,
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right?
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You're not helping each other out.
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You actually have to bring something
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that the other person lacks-- in that sense you complement.
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So are you actually bringing a functional gene
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that complements the gene deficiency in the other.
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