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These are the user uploaded subtitles that are being translated: 0 00:00:00,000 --> 00:00:04,770 MICHAEL HEMANN: Say you are in the lab 1 00:00:04,770 --> 00:00:10,860 and you've just identified a new strain, right? 2 00:00:10,860 --> 00:00:20,000 And so, we're going to call this strain hisX minus. 3 00:00:20,000 --> 00:00:22,880 So-- and I think this refers to a question that was put 4 00:00:22,880 --> 00:00:25,500 in the chat a little bit earlier on-- 5 00:00:25,500 --> 00:00:29,810 so hisX minus is a strain that can't grow 6 00:00:29,810 --> 00:00:32,159 without exogenous histidine. 7 00:00:32,159 --> 00:00:34,550 So it's a histidine auxotroph. 8 00:00:34,550 --> 00:00:36,740 But we don't know anything about what gene 9 00:00:36,740 --> 00:00:38,870 this mutation is in, right? 10 00:00:38,870 --> 00:00:41,240 And you've just developed this in lab, 11 00:00:41,240 --> 00:00:44,240 and you've been working on his3 for a while, 12 00:00:44,240 --> 00:00:46,250 and you want to know-- 13 00:00:46,250 --> 00:00:56,450 is hisX minus the same as his3 minus? 14 00:00:56,450 --> 00:00:59,180 Are they simply mutations in the same gene, 15 00:00:59,180 --> 00:01:03,050 or this represent a new gene that's mutated 16 00:01:03,050 --> 00:01:05,300 that causes the same phenotype? 17 00:01:05,300 --> 00:01:06,810 Well how do we figure this out? 18 00:01:06,810 --> 00:01:10,790 Well we figure it out by simply crossing these haploids 19 00:01:10,790 --> 00:01:13,520 together in what we'll call, essentially, 20 00:01:13,520 --> 00:01:16,240 a complementation test. 21 00:01:16,240 --> 00:01:18,270 So we're going to think, essentially, 22 00:01:18,270 --> 00:01:20,910 of two distinct possibilities. 23 00:01:20,910 --> 00:01:27,820 24 00:01:27,820 --> 00:01:32,970 And the first possibility is that hisX minus 25 00:01:32,970 --> 00:01:36,060 is the same as his3 minus. 26 00:01:36,060 --> 00:01:40,390 They're essentially mutations in the same gene. 27 00:01:40,390 --> 00:01:50,230 And so in this case, the diploid genotype 28 00:01:50,230 --> 00:01:57,550 is hisX minus over his3 minus. 29 00:01:57,550 --> 00:02:00,220 Or we can write that, if they're equivalent, 30 00:02:00,220 --> 00:02:06,010 as his3 minus over his3 minus. 31 00:02:06,010 --> 00:02:10,440 32 00:02:10,440 --> 00:02:17,290 And the phenotype of this, of course, is his minus. 33 00:02:17,290 --> 00:02:19,570 So if we're putting the same mutation in opposition 34 00:02:19,570 --> 00:02:21,880 to itself, we're not restoring function. 35 00:02:21,880 --> 00:02:25,240 And so we are now his minus. 36 00:02:25,240 --> 00:02:30,380 Well let's think of, then, the other possibility. 37 00:02:30,380 --> 00:02:36,960 And so the other possibility is hisX minus 38 00:02:36,960 --> 00:02:43,530 is not the same as his3 minus. 39 00:02:43,530 --> 00:02:47,550 And so the resulting diploid genotype 40 00:02:47,550 --> 00:02:58,280 is going to be hisX plus over hisX minus. 41 00:02:58,280 --> 00:03:06,990 And his3 minus over his3 plus. 42 00:03:06,990 --> 00:03:07,650 Why is that? 43 00:03:07,650 --> 00:03:10,560 Because we're dealing here with two distinct genes. 44 00:03:10,560 --> 00:03:14,430 And sort of the inferred phenotype of the haploids 45 00:03:14,430 --> 00:03:17,305 is that you are-- 46 00:03:17,305 --> 00:03:23,500 if you are hisX minus, you are his3 plus. 47 00:03:23,500 --> 00:03:25,490 And we can write sort of two genes in series. 48 00:03:25,490 --> 00:03:28,180 So these are two distinct genes-- hisX minus 49 00:03:28,180 --> 00:03:31,360 and his3 plus. 50 00:03:31,360 --> 00:03:38,770 Whereas the other strain would be hisX plus and his3 minus. 51 00:03:38,770 --> 00:03:40,330 So if we're just saying that they're 52 00:03:40,330 --> 00:03:41,740 a mutant for a single gene, we're 53 00:03:41,740 --> 00:03:44,480 assuming they're wild type for all of the others. 54 00:03:44,480 --> 00:03:47,890 And so in each case, you're bringing 55 00:03:47,890 --> 00:03:53,320 a functional copy of his3 and a functional copy of hisX 56 00:03:53,320 --> 00:03:54,820 into this cross. 57 00:03:54,820 --> 00:04:00,770 And so the resulting diploid genotype 58 00:04:00,770 --> 00:04:05,970 is going to be heterozygousity for both of these genes. 59 00:04:05,970 --> 00:04:07,950 And the phenotype is going to be-- 60 00:04:07,950 --> 00:04:13,390 61 00:04:13,390 --> 00:04:13,890 yeah. 62 00:04:13,890 --> 00:04:15,720 So there's a question-- are we assuming 63 00:04:15,720 --> 00:04:19,620 there's only one mutation in this synthesis pathway? 64 00:04:19,620 --> 00:04:21,779 We do assume that. 65 00:04:21,779 --> 00:04:25,410 And there are, I think, important ways 66 00:04:25,410 --> 00:04:29,580 that you actually make sure that that's actually the case-- 67 00:04:29,580 --> 00:04:32,880 where you actually are maintaining strains 68 00:04:32,880 --> 00:04:35,890 with the idea that there's only sort of single defects. 69 00:04:35,890 --> 00:04:37,623 Now we'll talk about this idea that maybe 70 00:04:37,623 --> 00:04:38,790 there are multiple defects-- 71 00:04:38,790 --> 00:04:40,630 I think in a couple of lectures. 72 00:04:40,630 --> 00:04:43,320 But the assumption is, if I say something 73 00:04:43,320 --> 00:04:47,925 is his3 minus, that is the only mutation within this pathway. 74 00:04:47,925 --> 00:04:50,590 75 00:04:50,590 --> 00:04:51,090 OK. 76 00:04:51,090 --> 00:04:56,340 So the resulting, you know, diploid in this case 77 00:04:56,340 --> 00:04:58,140 is going to be his plus. 78 00:04:58,140 --> 00:05:00,720 Because they have one functional copy of hisX, 79 00:05:00,720 --> 00:05:03,120 they have one functional copy of his3, 80 00:05:03,120 --> 00:05:07,110 these are actually compensating for the deficiency 81 00:05:07,110 --> 00:05:08,170 of each other. 82 00:05:08,170 --> 00:05:11,640 And so we're going to introduce this idea of complementation. 83 00:05:11,640 --> 00:05:17,710 84 00:05:17,710 --> 00:05:28,480 And complementation essentially means that the cross between-- 85 00:05:28,480 --> 00:05:31,450 or the progeny of a cross between two mutants 86 00:05:31,450 --> 00:05:32,740 is wild type. 87 00:05:32,740 --> 00:05:45,230 88 00:05:45,230 --> 00:05:51,860 Or haploids, or diploids, that have a mutant phenotype 89 00:05:51,860 --> 00:05:59,180 yields a wild type phenotype. 90 00:05:59,180 --> 00:06:03,280 So can you actually restore the function of the gene 91 00:06:03,280 --> 00:06:05,050 deficiency in the other strain? 92 00:06:05,050 --> 00:06:08,410 Can two strains that separately have 93 00:06:08,410 --> 00:06:11,350 a problem, or a phenotypic problem, 94 00:06:11,350 --> 00:06:13,550 restore function in that pathway? 95 00:06:13,550 --> 00:06:16,960 So if you have mutations in this same gene, 96 00:06:16,960 --> 00:06:19,930 you do not complement. 97 00:06:19,930 --> 00:06:23,380 If you have mutations in different genes, 98 00:06:23,380 --> 00:06:27,070 you do complement. 99 00:06:27,070 --> 00:06:28,930 So if you have a study group and you 100 00:06:28,930 --> 00:06:31,990 and your friend know exactly half of the material, 101 00:06:31,990 --> 00:06:34,363 but you know same half of the material, 102 00:06:34,363 --> 00:06:36,280 you're not actually complementing one another, 103 00:06:36,280 --> 00:06:36,550 right? 104 00:06:36,550 --> 00:06:38,080 You're not helping each other out. 105 00:06:38,080 --> 00:06:40,090 You actually have to bring something 106 00:06:40,090 --> 00:06:43,310 that the other person lacks-- in that sense you complement. 107 00:06:43,310 --> 00:06:46,150 So are you actually bringing a functional gene 108 00:06:46,150 --> 00:06:51,000 that complements the gene deficiency in the other. 7741

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