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Whoo!
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So let's continue practicing, guys.
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So in this exercise, what you have to do is to write a program that receives three integers.
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OK, that's the first step.
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And the program should print the following message divisible.
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If in each pair between these three numbers, there is at least one number in each pair, there is at
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least one number that can be divided by the other without a remainder.
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So once again, three integers and we can take pairs at any time from these three values.
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And we need to make sure that at any time there is at least one found that we can take one value and
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divided by the other in each pair and it will be divisible without a remainder.
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So, for example, let's take a look at a couple of examples.
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If we have the following three numbers, five, 10 and 20, then we know that we can print divisible
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message to the screen, because in this case, we know that if we take these pair five and 10, then
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10 is divided, can be divided by five without a remainder.
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And also, if we do it for 20 and ten and also for a 20 and five.
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Right.
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Twenty divided by five is four without a remainder.
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And also with they can look at another example.
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Another divisible example is three thirty six and seventy two.
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OK, they do not have to be like a ranged from the smallest to the largest.
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Right.
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It doesn't have anything to do with that.
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So basically we could simply use a seventy two, three and then thirty six.
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But still in this case if we take pairs, ok, we have one peer to peer and three pairs and, and at
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each pair we will have at least we will have basically just one number that can be divided by the other
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without a remainder.
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But if we will take a look at the following three numbers, for example, two, four seven or five,
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seven nine.
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Then in both of these cases, we can say that four maybe divided by two without a remainder.
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And that's OK.
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But seven cannot be divided by two or by four without a remainder.
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And it means that not all of the pairs in these three numbers are divisible.
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And that's why we should print a non divisible message to the screen and also five seven nine, which
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is obviously we cannot find even one pair, even one pair in these three numbers that can be divided.
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OK, that you take one number and you can divide it by the other.
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So that's basically what you have to do, is simply write a program, get three numbers from the user.
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And based on these pairs, OK, probably you will need to use want to use conditions based on these
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pairs.
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You will need to print corresponding message whether it's divisible.
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OK, that's just some terminology that we've created right now or if it's not divisible.
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So take your time.
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Think about it.
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And yeah, I think this is it for this video and I will see you in the solutions.
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