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These are the user uploaded subtitles that are being translated: 1 00:00:00,580 --> 00:00:08,080 All right, what is going on, guys, and this is a very interesting and very straightforward exercise 2 00:00:08,530 --> 00:00:13,310 that will utilize the usage of recursion concept. 3 00:00:14,260 --> 00:00:17,170 So what do we have to do here? 4 00:00:17,200 --> 00:00:18,280 So let's start. 5 00:00:18,670 --> 00:00:27,100 We have to write a function to we have to write a function that will do the following things. 6 00:00:28,290 --> 00:00:35,430 First of all, this recursive function should get some integer value, let's say none. 7 00:00:35,460 --> 00:00:44,600 OK, so the function is going to receive that will receive an integer value. 8 00:00:44,730 --> 00:00:45,280 None. 9 00:00:45,840 --> 00:00:50,790 OK, that's the first thing that our recursive function have to do. 10 00:00:51,060 --> 00:00:52,610 Recursive, right. 11 00:00:52,620 --> 00:00:59,250 We are talking about the recursion concept and we are going to use a recursive function. 12 00:01:00,150 --> 00:01:09,510 So this function is going to receive NUM and the way the function is going to work is basically to receive 13 00:01:09,690 --> 00:01:21,660 from the user a series of numbers of, let's say, natural numbers until the user will specify minus 14 00:01:21,660 --> 00:01:25,340 one, for example, for the stopping condition. 15 00:01:25,350 --> 00:01:37,710 So the function is going to read, let's say, a serious sequence of numbers from the user up until 16 00:01:38,040 --> 00:01:42,960 up until up until receiving minus one. 17 00:01:44,330 --> 00:01:50,900 And the function is going to return all of the numbers, basically not all the numbers. 18 00:01:53,020 --> 00:02:06,550 The total amount of numbers which are smaller than OK, so return, the total number is smaller, smaller 19 00:02:07,270 --> 00:02:10,640 than the value. 20 00:02:11,270 --> 00:02:11,830 All right. 21 00:02:12,100 --> 00:02:13,570 So let me discuss it. 22 00:02:14,350 --> 00:02:17,830 Let me tell you a little example. 23 00:02:17,890 --> 00:02:20,280 I think an example will be a good thing here. 24 00:02:21,130 --> 00:02:27,220 So, for example, if you receive OK, if you receive now equals to five. 25 00:02:27,400 --> 00:02:28,030 Oh, right. 26 00:02:28,540 --> 00:02:36,490 And you have a sequence of numbers from the user alike, I don't know, six, eight, 10. 27 00:02:36,490 --> 00:02:42,720 And then you have like three, one and seven and finally minus one. 28 00:02:43,330 --> 00:02:51,730 Then in this case your recursive function should just return to OK, so the function should return to 29 00:02:52,180 --> 00:02:53,380 why the function should return. 30 00:02:53,380 --> 00:03:01,810 Return to is because on every time that you have read some value from the user. 31 00:03:01,840 --> 00:03:07,750 OK, so you read the six, you read the eight, read 10, three one and so on and so forth, so on. 32 00:03:07,750 --> 00:03:13,900 Every duration that you've read, not the duration actually, but on a recursive call, you checked 33 00:03:13,900 --> 00:03:20,200 if a given number that you were reading is less than five, and if that's the case, you would simply 34 00:03:20,500 --> 00:03:21,900 take these into account. 35 00:03:21,910 --> 00:03:29,380 And finally return of the total numbers smaller than the naoum value than in this case, simply three 36 00:03:29,380 --> 00:03:33,910 and five are smaller than some, not including the stopping condition, which is minus one. 37 00:03:34,270 --> 00:03:38,440 And then basically you should return the value of two. 38 00:03:39,400 --> 00:03:42,270 So I hope the instructions are clear to you. 39 00:03:42,550 --> 00:03:51,340 And this exercise is not so trivial because I mean, there are a couple of things that we need to take 40 00:03:51,340 --> 00:03:52,780 into consideration. 41 00:03:52,780 --> 00:04:01,180 And one of these things is basically the fact that we don't really know in advance how many values the 42 00:04:01,180 --> 00:04:02,710 user will insert. 43 00:04:02,710 --> 00:04:02,940 Right. 44 00:04:02,950 --> 00:04:07,390 We don't know if it will be one, two, three, five and so on and so forth. 45 00:04:07,430 --> 00:04:14,500 OK, and the second thing that we have to take into consideration is the fact that we cannot use here 46 00:04:14,770 --> 00:04:23,560 some standard while loop and to like read the values from the user, because that's the Terentiev approach 47 00:04:23,560 --> 00:04:25,120 to solve this exercise. 48 00:04:25,510 --> 00:04:31,000 But we want the recursive approach using recursive functions. 49 00:04:31,330 --> 00:04:35,620 OK, so these are the two things that you have to bear in mind. 50 00:04:36,490 --> 00:04:43,150 And also once we are going to start solving this exercise, what you also have to bear in mind is the 51 00:04:43,150 --> 00:04:49,890 fact that you have to think of a way to construct these recursive function. 52 00:04:50,650 --> 00:04:54,490 So you guys take your time. 53 00:04:54,490 --> 00:05:01,540 Please take at least five, 10, even half an hour to think of this solution. 54 00:05:01,540 --> 00:05:09,550 Try to write down everything on your on your own and to understand how you would have been you would 55 00:05:09,550 --> 00:05:14,190 have implemented this on this function. 56 00:05:14,800 --> 00:05:22,840 And until you do, I will be waiting for you and I will see you in the next video where we are going 57 00:05:22,840 --> 00:05:25,240 to solve this exercise together. 58 00:05:25,270 --> 00:05:26,920 So until then, good luck. 5850

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