All language subtitles for 02 - Calculate compound probabilities

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Would you like to inspect the original subtitles? These are the user uploaded subtitles that are being translated: 1 00:00:00,005 --> 00:00:01,006 - [Instructor] In the previous movie, 2 00:00:01,006 --> 00:00:04,005 I described how to calculate simple probabilities, 3 00:00:04,005 --> 00:00:08,006 that is the probability of a single trial. 4 00:00:08,006 --> 00:00:12,005 In this movie, I will describe compound probabilities. 5 00:00:12,005 --> 00:00:14,006 Compound probabilities assume that you 6 00:00:14,006 --> 00:00:18,003 want to analyze multiple independent trials. 7 00:00:18,003 --> 00:00:22,009 And by independent, that means that the second trial 8 00:00:22,009 --> 00:00:26,000 or outcome, in other words, the second flip of a coin 9 00:00:26,000 --> 00:00:30,003 or a throw of a die, is independent of the first. 10 00:00:30,003 --> 00:00:32,004 If you do have multiple independent trials, 11 00:00:32,004 --> 00:00:34,004 then you will multiply probability 12 00:00:34,004 --> 00:00:36,009 to get a compound probability. 13 00:00:36,009 --> 00:00:40,005 So flipping a coin will end up on heads half the time. 14 00:00:40,005 --> 00:00:43,003 So the probability of getting heads twice in a row 15 00:00:43,003 --> 00:00:45,006 assuming that the coin is fair 16 00:00:45,006 --> 00:00:50,004 would be one half times one half equals one quarter. 17 00:00:50,004 --> 00:00:53,004 One easy mistake to make is 18 00:00:53,004 --> 00:00:56,003 to assume that compound probability 19 00:00:56,003 --> 00:00:57,006 after you've already started. 20 00:00:57,006 --> 00:01:00,008 In other words, one of the trials has been done. 21 00:01:00,008 --> 00:01:02,003 If you're flipping a coin, 22 00:01:02,003 --> 00:01:03,007 again, a fair coin, 23 00:01:03,007 --> 00:01:07,008 with a one half probability of getting heads 24 00:01:07,008 --> 00:01:09,007 and you flip and get heads, 25 00:01:09,007 --> 00:01:12,003 the probability of flipping heads twice in a row 26 00:01:12,003 --> 00:01:14,002 is no longer one quarter. 27 00:01:14,002 --> 00:01:16,009 It is one half because you've already done it once. 28 00:01:16,009 --> 00:01:20,006 And all that matters is the second trial 29 00:01:20,006 --> 00:01:25,005 which is 50% or one half likely to end up on heads. 30 00:01:25,005 --> 00:01:27,006 To visualize the probabilities, 31 00:01:27,006 --> 00:01:29,009 I have created a chart. 32 00:01:29,009 --> 00:01:34,006 And you can see that I have two separate trials in the rows. 33 00:01:34,006 --> 00:01:38,006 In the first we have independent outcomes rolling a die. 34 00:01:38,006 --> 00:01:40,006 And we're asking the probability 35 00:01:40,006 --> 00:01:44,000 of rolling a three on the first outcome 36 00:01:44,000 --> 00:01:47,001 and rolling a three again on the second one. 37 00:01:47,001 --> 00:01:48,008 Assuming everything is independent, 38 00:01:48,008 --> 00:01:51,004 then we have one chance out of six, 39 00:01:51,004 --> 00:01:54,000 each of those trials to come up a three. 40 00:01:54,000 --> 00:01:59,001 So that would be 1/6 times 1/6 equals 1/36. 41 00:01:59,001 --> 00:02:01,001 So we have one chance out of 36 42 00:02:01,001 --> 00:02:04,008 or 35 to one odds against. 43 00:02:04,008 --> 00:02:06,009 We might also ask what is the probability 44 00:02:06,009 --> 00:02:10,006 of rolling exactly a three on the first outcome 45 00:02:10,006 --> 00:02:11,008 and not rolling a three, 46 00:02:11,008 --> 00:02:13,006 in other words getting any other number 47 00:02:13,006 --> 00:02:15,006 on the second outcome? 48 00:02:15,006 --> 00:02:19,002 Well, for that, we have our probability of 1/6 49 00:02:19,002 --> 00:02:20,004 of rolling a three, 50 00:02:20,004 --> 00:02:23,005 and then we have five out of six numbers 51 00:02:23,005 --> 00:02:26,007 that would allow us to succeed in our scenario. 52 00:02:26,007 --> 00:02:29,008 So we multiply 1/6 by 5/6, 53 00:02:29,008 --> 00:02:32,006 and get 5/36. 54 00:02:32,006 --> 00:02:34,008 And those numbers make sense. 55 00:02:34,008 --> 00:02:36,005 If we look back at the first row 56 00:02:36,005 --> 00:02:40,007 and we see that we have 1/36 of rolling a three, 57 00:02:40,007 --> 00:02:43,006 if we add that to 5/36 in the second row 58 00:02:43,006 --> 00:02:45,001 where we don't roll a three, 59 00:02:45,001 --> 00:02:48,007 we get 6/36, which is 1/6, 60 00:02:48,007 --> 00:02:52,000 and is the probability of rolling a three 61 00:02:52,000 --> 00:02:53,008 in the first place. 62 00:02:53,008 --> 00:02:56,007 Compound probabilities can get a little tricky, 63 00:02:56,007 --> 00:02:58,005 but after you make sure 64 00:02:58,005 --> 00:03:01,005 that the results of your trials are independent 65 00:03:01,005 --> 00:03:03,006 you can use multiplication to find 66 00:03:03,006 --> 00:03:06,008 the compound probability of the composite outcome 67 00:03:06,008 --> 00:03:08,000 you're looking for. 5127

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